# a conversion from decimal to hex and vise versa

I need 3 VBScript functions something like
- convertToHex(decnumber)
- convertToDecimal(hexnumber)
- shift right function

Now that may sound easy but I cannot arrive to make the conversion function to work for the values

4294967295 for convertToHex
FFFFFFFF for convertToDecimal

I get an overflow message error.
And the last function, the shift right, is also wrong by 1! Try it with shr(4294967295,4) to understand what I mean and check the result with MS calculator.

My functions:
'Return a long number in hexadecimal (i.e. hex(69) )
function hexa(n)
tmpResult = hex(n)
for i=len(tmpResult) to 7 step 1
tmpResult = "0" + tmpResult
next
hexa = LCase(tmpResult)
end function

'Return a hexadecimal number in decimal (i.e. deci(&HFF) )
function deci(n)
deci = clng(n)
end function

'function shift right by b
function shr(a,b)
for i=1 to b step 1
a = int(a/2)
next
shr = a
end function

Maybe you guys can end up with a solution.
###### Who is Participating?

Commented:
I have no idea what you're doing in calculator, but if you switch to hex mode type in FFFFFFFF and divide it by 2 (4 times) you get the following:

FFFFFFFF / 2 =
7FFFFFFF / 2 =
3FFFFFFF / 2 =
1FFFFFFF / 2 =
FFFFFFF =  268435455 (decimal)

Which is the exact same result that you get via your shift function.  I don't know what procedure you're following to get your result, but whatever it is you're doing you're getting an incorrect result.  I'm assuming that you're going through the procedure incorrectly and doing some kind of rounding somewhere (e.g., you may be switching back and forth between hex and decimal or something when you've got fractional parts).

It's intuitively obvious your calculator result is wrong.  If you right shift a binary number made up of all ones (like FFFFFFFF), you're going to end up with an odd number as the least significant bit will always be one.
0

Author Commented:
Adjusted points from 50 to 100
0

Commented:
Are you aware that there is an hex function already in ASP?

the format hex(number)

so

x= hex(69) 'should assign a value of  45 to x
0

Commented:
BTW running the hex function for gives me an overflow error also.  I suspect there's an upper limit to the hex function

0

Commented:
And I have no idea what the shift right function should return.  what is it? if you dont mind the question

mberumen
0

Commented:
You're forgetting that a long represents a SIGNED 32-bit number.  So the valid range for a long is:

-2147483648 to 2147483647

Because it's signed:

FFFFFFFF = -1 (not 4294967295)

If you want to deal with unsigned numbers you have to do a little bit of manipulation.

function hexa(n)
temp = n
if temp > 2147483647 then 'convert it to its corresponding negative value
temp = temp - 4294967296
end if
hexa = hex(temp)
end function

function deci(n)
temp = clng(n)
if temp < 0 then temp =  4294967296 + temp 'convert it to an unsigned value
deci = temp
end function

function shr(a,b)
for i=1 to b step 1
a = int(a / 2)
next
shr = a
end function

response.write shr(4294967295,4) & "<BR>"
response.write deci(&hFFFFFFFF) & "<BR>"
response.write hexa(4294967295) & "<BR>"

And your shift function is working fine.

0xFFFFFFFF (unsigned 4294967295) >> 4 = 0x0FFFFFFF (268435455)

Which is what it produces.

0

Author Commented:
To mberumen:
Shift right mean that a binary number like 0101110 will become 0010111

To clockwatcher:
Big thanks but I still don't understand how come my shift is working? I mean if I try using MS calculator and input FFFFFFFF divide it by 2 four times and click on decimal, I will get 268435456!

Any idea why?
0

Author Commented:
Big thanks go to clockwatcher
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.