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Odd & Even Number.

hi,

How to detect the input number is odd or even number?
0
zamirjalil
Asked:
zamirjalil
  • 2
1 Solution
 
setiawanCommented:
Hi zamirjalil,

It is easy,

just mod the number with 2, if the result equal to zero then It is even others is odd

<% if (a mod 2) = 0 then
      response.write "Even"
   else
      response.write "Odd"  
   end if
%>
  danny
0
 
zamirjalilAuthor Commented:
Thanks danny,
BTW anything wrong with my code?

<%
if request("bdate")<> "" or request("bkod")<>"" or request("bjan")<>"" then

if Isdate(request("bdate")) then
 birthdate=request("bdate")
 age=datediff("yyyy",date(),birthdate)
else
birthdate=Cdate(mid(request"bdate"),3,2)&"/"&mid(request("bdate"),5,2)&"/"&left(request("bdate"),2))
age=datediff("yyyy",birthdate,date())
response.write "Your age now is:" & age & " years old."
end if

 if IsNumeric(request("bjan")) then
  inumur = request("bjan")
  if (inumur mod 2) = 0 then
   response.write inumur & "is an EVEN  number."
   response.write "You r a girl!"
  else
   response.write inumur & "is an ODD number."
   response.write "You r a man!"
  end if
end if %>
0
 
zamirjalilAuthor Commented:
sorry..a careless mistake...i found it. missing end if statement. Thanks everybody.
0

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