[Last Call] Learn how to a build a cloud-first strategyRegister Now

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 190
  • Last Modified:

searching in a recordset

I have a record set defined as follows:

Dim rs_VendorList As New ADODB.Recordset
    rs_VendorList.CursorLocation = adUseClient
  rs_VendorList.Open SQLquery, ConnectionString, adOpenDynamic

There are no problem using the recordset. Later in the code I get a value and I would like ot search for that value in the recordset. I have ound the "recordset.find" method but I cannot make it work. Can anyone help me with this one?




0
scotts27
Asked:
scotts27
1 Solution
 
TchalkovCommented:
try
 rs_VendorList.find <criteria>

 if rs_VendorList.Eof then
'not found
else
' found
end if
0
 
BobbyOwensCommented:
I have tried the following code using the .Find and it worked. What is the error you are getting back, or what is happening?

Dim arsTest As ADODB.Recordset
 
  Set arsTest = New ADODB.Recordset
  arsTest.ActiveConnection = pacnNavigatorData
  arsTest.CursorLocation = adUseClient
arsTest.Open "SELECT * FROM fst_system", , adOpenDynamic
  arsTest.Find "SystemID='7ae72a1c-d406-11d3-842a-000629a66eb4'"
  Set arsTest = Nothing

When you do the find, you need to enter the full criteria you are looking for. What is the back end database you are using?
0
 
Éric MoreauSenior .Net ConsultantCommented:
Before calling the find method, use rs_VendorList.MoveFirst.

Also, be advised that the Find method allow only one criteria!
0
 
rajeshkhatriCommented:
the syntax for finding the value in the recordset will be

rs.find <condition> , , as searchforward

rs is the recordset created through
set rs = new  ADODB.recordset

why searchforward because it search the record faster then other


0

Featured Post

Concerto Cloud for Software Providers & ISVs

Can Concerto Cloud Services help you focus on evolving your application offerings, while delivering the best cloud experience to your customers? From DevOps to revenue models and customer support, the answer is yes!

Learn how Concerto can help you.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now