Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people, just like you, are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
Solved

How to know the ID of the control who received an event

Posted on 2000-05-13
1
190 Views
Last Modified: 2013-11-20
Hi...

I have placed some ActiveX controls in a Dialog Resource. Those controls have to make some actions when the mouse is over or has clicked on it. I'm planning to use only 1 event handler to accomplish the actions for all controls so I need to know the ID of the control who has thrown the event.

How can I do it?
Thanks in advance

Demarcy
0
Comment
Question by:demarcy
1 Comment
 
LVL 8

Accepted Solution

by:
VinExpert earned 50 total points
ID: 2807914
Hi,

Map the PreTranslateMessage(...) message handler to that dialog. And modify the code as

BOOL CMyDlg::PreTranslateMessage(MSG* pMsg)
{
      if(pMsg->message == WM_MOUSEMOVE)
      {
            CRect rect;
            GetDlgItem(IDC_EDIT1)->GetWindowRect(rect);
            if(rect.PtInRect(pMsg->pt))
            {
                  AfxMessageBox("Mouse On The Edit Box");
                  return CDialog::PreTranslateMessage(pMsg);
            }
            
            GetDlgItem(IDC_LIST1)->GetWindowRect(rect);
            if(rect.PtInRect(pMsg->pt))
            {
                  AfxMessageBox("Mouse On The List Box");
                  return CDialog::PreTranslateMessage(pMsg);
            }

            GetDlgItem(IDC_MY_DBGRID)->GetWindowRect(rect);
            if(rect.PtInRect(pMsg->pt))
            {
                  AfxMessageBox("Mouse On The DB Grid Box");
                  return CDialog::PreTranslateMessage(pMsg);
            }

            GetDlgItem(IDOK)->GetWindowRect(rect);
            if(rect.PtInRect(pMsg->pt))
            {
                  AfxMessageBox("Mouse On The OK Button");
                  return CDialog::PreTranslateMessage(pMsg);
            }

      }
      return CDialog::PreTranslateMessage(pMsg);
}

here I have taken some normal controls and a activex dbgrid control. U can make out by thier ID. But here U R not getting the ID's but, u will know where the mouse is. So u can replace the AfxMessageBox() with Ur function call and their U know the id also as if it says I am in DBGrid, then ID is known as ID_MY_DBGRID.

Hope this helps.

VinExpert
0

Featured Post

Free Tool: Site Down Detector

Helpful to verify reports of your own downtime, or to double check a downed website you are trying to access.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Introduction: Dynamic window placements and drawing on a form, simple usage of windows registry as a storage place for information. Continuing from the first article about sudoku.  There we have designed the application and put a lot of user int…
Introduction: Database storage, where is the exe actually on the disc? Playing a game selected randomly (how to generate random numbers).  Error trapping with try..catch to help the code run even if something goes wrong. Continuing from the seve…
This video will show you how to get GIT to work in Eclipse.   It will walk you through how to install the EGit plugin in eclipse and how to checkout an existing repository.
This video shows how to use Hyena, from SystemTools Software, to bulk import 100 user accounts from an external text file. View in 1080p for best video quality.

837 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question