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Grep a single line out of file?

Posted on 2000-05-16
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Last Modified: 2008-02-26
I need a shell script that will return a single value from a file given a particular line.  For example a file contains:

10
20
30
33
44

I need a command that can return the value 33 when passed in the param 4, for line 4.

Thanks,
Ethan
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Question by:epost
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geotiger earned 200 total points
ID: 2814680
One liner will do:

cat yourfile | awk '{if (NR==4) print $0}'

This will print the fourth line. If you want just print particular field in the line. Please let me know.
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Author Comment

by:epost
ID: 2815180
Cool, how can I turn the line number into a variable?   When I use $1 it thinks I mean a column.
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Expert Comment

by:geotiger
ID: 2815388
Yes, say, if you want to print out all the lines with the first column eq 33, you can do it as

$ echo "33 34\n34 35\n33 36\n37 45" | awk '{if ($1==v) print $0}' v=33
33 34
33 36

If these lines are in a file, you can just use cat or just put it in the end.

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