Go Premium for a chance to win a PS4. Enter to Win

x
?
Solved

Very very easy question

Posted on 2000-05-17
6
Medium Priority
?
178 Views
Last Modified: 2010-04-02
If I have object bigcookie
class cookie{
public:
int chocolatechips;
};
cookie bigcookie;

and a function in a namespace:
namespace foodfuncs{
void bigcookie(void){}
}

If I say 'using foodfuncs' bigcookie thenceforth refers to foodfuncs::bigcookie.

How do I make it refer to the cookie object again? Am I right in thinking it is a compile-time issue, and in the executable, these two entities will have different names?

Thank you
0
Comment
Question by:glebspy
  • 3
  • 2
6 Comments
 

Expert Comment

by:forza
ID: 2818589
>How do I make it refer to the cookie object again?
What do you mean by "again"?
You cannot have the bigcookie func refer to the object. Why would you do that?
0
 
LVL 1

Author Comment

by:glebspy
ID: 2818614
ok I have the above followed by:

void main(void);
cookie bigcookie;
bigcookie.chocolatechips=1;

//Now I use the namespace
using foodfuncs:
bigcookie();

//ok so far so good but now I want to
//be able to say
bigcookie.chocolatechips=3;
//which I can't because thanks to my //using statement bigcookie means
//the function bigcookie

So now I hope you understand the question
thank you
0
 
LVL 1

Author Comment

by:glebspy
ID: 2818624
ok I have the above followed by:

void main(void);
cookie bigcookie;
bigcookie.chocolatechips=1;

//Now I use the namespace
using foodfuncs:
bigcookie();

//ok so far so good but now I want to
//be able to say
bigcookie.chocolatechips=3;
//which I can't because thanks to my //using statement bigcookie means
//the function bigcookie

So now I hope you understand the question
thank you
0
Concerto Cloud for Software Providers & ISVs

Can Concerto Cloud Services help you focus on evolving your application offerings, while delivering the best cloud experience to your customers? From DevOps to revenue models and customer support, the answer is yes!

Learn how Concerto can help you.

 
LVL 22

Accepted Solution

by:
nietod earned 10 total points
ID: 2818974
Try

::bigcookie.chocolatechips=3;

0
 
LVL 1

Author Comment

by:glebspy
ID: 2819064
I really wanted to know how to reverse the effect of the 'using' statement for good, rather than just that one instance - still I guess its worth 5 points
0
 
LVL 22

Expert Comment

by:nietod
ID: 2819250
>> I really wanted to know how to reverse
>> the effect of the 'using' statement for good
Then you should have asked that.

And you should not have given a bad grade for an answer that was correct, but just not what you wanted--especially since I didn't answer. I would much much rather have not had the points than have a bad grade in my record.

I believe that a using declaration obeys scope rules.  So use it inside a scope and it will not extend outside of that scope.
0

Featured Post

Hire Technology Freelancers with Gigs

Work with freelancers specializing in everything from database administration to programming, who have proven themselves as experts in their field. Hire the best, collaborate easily, pay securely, and get projects done right.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Errors will happen. It is a fact of life for the programmer. How and when errors are detected have a great impact on quality and cost of a product. It is better to detect errors at compile time, when possible and practical. Errors that make their wa…
Many modern programming languages support the concept of a property -- a class member that combines characteristics of both a data member and a method.  These are sometimes called "smart fields" because you can add logic that is applied automaticall…
The goal of the video will be to teach the user the concept of local variables and scope. An example of a locally defined variable will be given as well as an explanation of what scope is in C++. The local variable and concept of scope will be relat…
The viewer will learn how to user default arguments when defining functions. This method of defining functions will be contrasted with the non-default-argument of defining functions.

971 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question