how to deliver the url string as a parameter in the url

I want to deliver the url string  as a request parameter to next page ,but the system trucate some information.the part codes are showed as follows.

the html code:
<html>
<body>
<form name="form1" method="post" action="/test/testurl.jsp?url='/servlet/page.go?pagenum=1&pa=adb'&pagerow=3">

   <INPUT TYPE="text" NAME="testname" >

   <INPUT TYPE="submit" NAME="commit" ID="commit" VALUE="commit">
</form>

testurl.jsp:

<html>
<body>
URL test


  <%
      String testname = request.getParameter("testname");
      String url      = request.getParameter("url");
      String pagerow  = request.getParameter("pagerow");
      out.println("testname=" + testname);
      out.println("<br>");
      out.println("url=" + url);
            out.println("<br>");
      out.println("pagerow=" + pagerow);
  %>

</body>


the result page:

<html>
<body>
URL test
  testname=dgdfgdssdgfdsgfsd
<br>
url=/servlet/page.go?pagenum=1
<br>
pagerow=3

</body>

the url string was trucated.Can you give me some advices,Thank you first.
jianminAsked:
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iboConnect With a Mentor Commented:
white spaces is not allowed in url (in between parameters)
u can use the method :
java.net.URLEncoder.encode(myString)
to encode special characters and string w/ white spaces
into a valid url.
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iboCommented:

and yes.. the single quote is not allowed (special char bot allowed in url addy). use the method i mentioned.

StringBuffer myUrl = new StringBuffer();
myUrl.append("/test/testurl.jsp?url=").append(java.net.URLEncoder.encode('/servlet/page.go?pagenum=1&pa=adb').append("&pagerow=3">);
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iboCommented:
..

<form name="form1" method="post" action="<%= myUrl.toString() %>">
0
 
SpideyModCommented:
Force Accepted

SpideyMod
Community Support Moderator @Experts Exchange
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