asked on

how to deliver the url string as a parameter in the url

I want to deliver the url string as a request parameter to next page ,but the system trucate some information.the part codes are showed as follows.

the html code:
<html>
<body>
<form name="form1" method="post" action="/test/testurl.jsp?url='/servlet/page.go?pagenum=1&pa=adb'&pagerow=3">

<INPUT TYPE="text" NAME="testname" >

<INPUT TYPE="submit" NAME="commit" ID="commit" VALUE="commit">
</form>

testurl.jsp:

<html>
<body>
URL test

<%
String testname = request.getParameter("testname");
String url = request.getParameter("url");
String pagerow = request.getParameter("pagerow");
out.println("testname=" + testname);
out.println("<br>");
out.println("url=" + url);
out.println("<br>");
out.println("pagerow=" + pagerow);
%>

</body>

the result page:

<html>
<body>
URL test
testname=dgdfgdssdgfdsgfsd
<br>
url=/servlet/page.go?pagenum=1
<br>
pagerow=3

</body>

the url string was trucated.Can you give me some advices,Thank you first.

ASKER CERTIFIED SOLUTION

ibo

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ibo

and yes.. the single quote is not allowed (special char bot allowed in url addy). use the method i mentioned.

StringBuffer myUrl = new StringBuffer();
myUrl.append("/test/testurl.jsp?url=").append(java.net.URLEncoder.encode('/servlet/page.go?pagenum=1&pa=adb').append("&pagerow=3">);

ibo

..

<form name="form1" method="post" action="<%= myUrl.toString() %>">

SpideyMod

Force Accepted

SpideyMod
Community Support Moderator @Experts Exchange