Solved

Set object whit a variable name

Posted on 2001-06-04
2
147 Views
Last Modified: 2010-05-02
I want to make a function who get a param name and will create a object whit this name ex.:

'my sub:
Sub CreateObj(UserId as integer)
   Dim "UserId" & UserId as MyObject
   SET "UserId" & UserId = New MyObject
End Sub

if i send 10 to the function this will make the same thing than:

Dim UserId10 as MyObject
SET UserId10 = New MyObject

How can i make my sub for it works ?
0
Comment
Question by:mammouth
2 Comments
 
LVL 43

Accepted Solution

by:
TimCottee earned 75 total points
ID: 6152145
You cannot do this in quite the way you describe. You can however declare an array of objects and reference them like that:

Dim aryMyObjects(10) As MyObject

Sub CreateObj(UserID As Integer)
  Set aryMyObjects(UserID) = New MyObject
End Sub

Or with a collection

Dim colMyObjects As Collection

Private Sub Form_Load()
  Set colMyObjects = New Collection
End Sub

Sub CreateObject(UserID As Integer)
  Dim NewObject As MyObject
  Set NewObject = New MyObjects
  colMyObjects.Add NewObject,UserID
End Sub

You can then refer to the created object using

colMyObjects(UserID).Property
0
 
LVL 2

Expert Comment

by:WalterM
ID: 6156267
Why would you want to do this?

Names that you give to variables are used only from within your source code, not in the compiled binary (except for debugging information). Dynamically generating variable names is only useful for Add-Ins and code generators.

If you need to be able to discern between objects, I suggest you add a property to your class that stores the User ID as mentioned in your example. Assuming you call the property "UserID", then you can code your creation function as follows:

   Function CreateObj(UserId as integer) As MyObject
      Set CreateObj = New MyObject
      CreateObj.UserID = UserID
   End Sub

Use the function like this:

   Dim O As MyObject
   Set O = CreateObj(10)

To inspect the User ID of any MyObject instance, use the property as in:

   If O.UserID = 10 Then ...

Optionally, you could store the created objects in a collection:

   Dim MyObjects As Collection

   Function CreateObj(UserID As Integer) As MyObject
      Set CreateObj = New MyObject
      CreateObj.UserID = UserID
      MyObjects.Add CreateObj, CStr(UserID)
   End Sub

so you can enumerate them:

   Dim O As MyObject
   For Each O in MyObjects
      Debug.Print O.UserID
   Next O

and retrieve one by it's UserID:

   Dim O As MyObject
   Set O = MyObjects.Item("10")

This way, you don't need to declare a variable for each object instance you're application requires, because you can retrieve the required instance from the collection into a temporary variable of the type MyObject.

Michel
0

Featured Post

Free Tool: SSL Checker

Scans your site and returns information about your SSL implementation and certificate. Helpful for debugging and validating your SSL configuration.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

The debugging module of the VB 6 IDE can be accessed by way of the Debug menu item. That menu item can normally be found in the IDE's main menu line as shown in this picture.   There is also a companion Debug Toolbar that looks like the followin…
Since upgrading to Office 2013 or higher installing the Smart Indenter addin will fail. This article will explain how to install it so it will work regardless of the Office version installed.
Get people started with the process of using Access VBA to control Excel using automation, Microsoft Access can control other applications. An example is the ability to programmatically talk to Excel. Using automation, an Access application can laun…
This lesson covers basic error handling code in Microsoft Excel using VBA. This is the first lesson in a 3-part series that uses code to loop through an Excel spreadsheet in VBA and then fix errors, taking advantage of error handling code. This l…

829 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question