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Php and mysql

Posted on 2001-06-06
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Last Modified: 2006-11-17
I have a mysql database that lists 5 thousand businesses and i have wrote a php page that will pull back the first 5 listings and tell the person how many are relative to there seach.

So all businesses in essex will show the first 5 and say there are a total of 88.

how do i make it so that it will say there are x ammount of pages so that the user can click on the page number or next or prvious

like Altavista

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Question by:Boroughman
  • 3
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6 Comments
 
LVL 2

Expert Comment

by:higijj
ID: 6161514
Well.. you do one queries to get the total number of business

and divide it by 5 to get the number of pages.

0
 

Accepted Solution

by:
hongs earned 150 total points
ID: 6162375
The total records:$totalcount=mysql_num_rows($result);
The total pages:$totalpages=ceil($totalcount/5);
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Expert Comment

by:hongs
ID: 6162491
<?
//A simple sample

$hostname="localhost";
$username="root";
$password="";
$dbname="db1";
mysql_connect($hostname,$username,$password);
mysql_select_db($dbname);
$query="select field1,fields from table1";
$result=mysql_query($query);

$intCount=mysql_num_rows($result);     //Total records
$intEach=5;                    //Records each page
$intPages=ceil($intCount/$intEach);     //Total Pages
if(!$intPage)
     $intPage=1;               //page No
     

mysql_data_seek($result,($intPage-1)*$intEach);
for($i=0;$i<5;$i++)
{
     if($row=mysql_fetch_row($result))
     print $row[0]."-".$row[1]."<BR>\n";
}

print "<HR>";
if($intPage>1)
     print "<a href=\"".basename($PHP_SELF)."?intPage=".($intPage-1)."\">Prev Page</a>|";
else
     print "Prev Page|";
if($intPage<$intPages)
     print "<a href=\"".basename($PHP_SELF)."?intPage=".($intPage+1)."\">Next Page</a>|";
else
     print "Next Page|";
print $intPage." of ".$intPages;
?>
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Author Comment

by:Boroughman
ID: 6162859
could you do it so that it look like this



Results Pages: 1|2|3|4|5|6|7|8|9|10 [Next >>]
0
 

Expert Comment

by:hongs
ID: 6166267
<?
//A simple sample.
//Results Pages: 1|2|3|4|5|6|7|8|9|10 [Next >>]

$hostname="localhost";
$username="root";
$password="";
$dbname="db1";
mysql_connect($hostname,$username,$password);
mysql_select_db($dbname);
$query="select field1,field2 from step";
$result=mysql_query($query);

$intCount=mysql_num_rows($result);     //Total records
$intEach=5;                    //Records each page
$intPages=ceil($intCount/$intEach);     //Total Pages
if(!$intPage) $intPage=1;          //page No
     
$intEachFrame=10;               //Pages each frame
$intFrame=ceil($intPage/$intEachFrame);     //Frame No.
$intFrames=ceil($intPages/$intEachFrame);//Total Frames

mysql_data_seek($result,($intPage-1)*$intEach);
for($i=0;$i<$intEach;$i++)
{
     if($row=mysql_fetch_row($result))
     print $row[0]."-".$row[1]."<BR>\n";
}

print "<HR>";
if($intFrame>1)
     print "<a href=\"".basename($PHP_SELF)."?intPage=".($intFrame-1)*$intEachFrame."\">[<< Prev]</a>|";

$temp1=($intFrame-1)*$intEachFrame;
for($j=1;$j<=$intEachFrame;$j++)
{
     $temp=$temp1+$j;
     if($temp<=$intPages)
     {
          if($temp==$intPage)
               print "<a href=\"".basename($PHP_SELF)."?intPage=".$temp."\"><label style='color:red'>".$temp."</label></a>";
          else
               print "<a href=\"".basename($PHP_SELF)."?intPage=".$temp."\">".$temp."</a>";
     }
     else
     {
          print $temp;
     }
     if($j==$intEachFrame)
          print " ";
     else
          print "|";
}    

if($intFrame<$intFrames)
     print "<a href=\"".basename($PHP_SELF)."?intPage=".($intFrame*$intEachFrame+1)."\">[Next >>]</a>";
else
     print "[Next >>]";


?>
0
 

Author Comment

by:Boroughman
ID: 6199483
im now using your first answer with the next and back button but if the result is 0 i get an error
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