Solved

removing element from array during loop

Posted on 2001-06-09
1
300 Views
Last Modified: 2008-03-06
@list=(1,3,7,2,8,9);
$othernumber=8;

foreach $number(@list)
 {
  if($number==$othernumber)
   {
    # remove $number from @list
   };
 };
0
Comment
Question by:superquestions
1 Comment
 
LVL 84

Accepted Solution

by:
ozo earned 50 total points
ID: 6172019
@list = grep { $_!=$othernumber } @list
0

Featured Post

Free Tool: Site Down Detector

Helpful to verify reports of your own downtime, or to double check a downed website you are trying to access.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

On Microsoft Windows, if  when you click or type the name of a .pl file, you get an error "is not recognized as an internal or external command, operable program or batch file", then this means you do not have the .pl file extension associated with …
A year or so back I was asked to have a play with MongoDB; within half an hour I had downloaded (http://www.mongodb.org/downloads),  installed and started the daemon, and had a console window open. After an hour or two of playing at the command …
Explain concepts important to validation of email addresses with regular expressions. Applies to most languages/tools that uses regular expressions. Consider email address RFCs: Look at HTML5 form input element (with type=email) regex pattern: T…

730 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question