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Templatized defines...

Posted on 2001-06-14
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I am writing a large project. One of the namespaces is "Utility", where I'll have things like Vectors, Lists etc.
I use the STL, but want to get away from some of it's naming, so that should some of it's funtionality prove insufficient, I will replace the classes with my own implementations. I also want to restrict the template parameters for the STL containers in use, because I do my own memory management, and provide a class that is interface compatible with std::allocator.

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Question by:Tom_P
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7 Comments
 

Author Comment

by:Tom_P
ID: 6193746
So this is the scenario:
namespace Memory
{
 class MemoryManager {/*...*/}; //allocator compatible
}

Now I want to be able to do something like this:

namespace Utility
{
//this is the idea
  template<class T>
  typedef std::vector<T, Memory::MemoryManager<T> > Vector;
}

And then use the new type like, e.g.

Utility::Vector<int> v(/*which ever ctor*/);

Basically define a type that has one of the template arguments restricted, and hopefully rename the thing as well.
I don't think it is possible in C++, maybe just by deriving from std::vector and providing a similar set of ctors and a dtor. But should anyone have any bright ideas I will show appreciation accordingly.
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Expert Comment

by:ambience
ID: 6193914
I used

template <class T>
class Vector : public std::vector<T,Memory::MemoryManager<T> > 
{
};

and this worked...

typedef std::vector<T, Memory::MemoryManager<T> > Vector;

doing that how would you supply the type T when you want to instantiate a Vector ??
I dont think this is possible , why ... well , i am not sure about that, i guess this has to do with the semantics  of typedefs , i'll be happy to know that if anyone could help here.

you cannot even try doing the following
typedef std::vector<T, Memory::MemoryManager<T> > Vector<T>;

as Vector<T> is not a valid typename.

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LVL 9

Expert Comment

by:jasonclarke
ID: 6194674
C++ doesn't allow templated typedefs, but there are workarounds.

Take a look at this link to a Guru of the Week:

http://www.gotw.ca/gotw/079.htm
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Accepted Solution

by:
jasonclarke earned 800 total points
ID: 6194687
Basically, the GoTW solution would be this:

template <class T>
struct Vector
{
    typedef std::vector<T, Memory::MemoryManager<T> > Type;
};

then you could declare objects like this:

Vector<int>::Type v(...);

it may be a little less pretty than other things, but the meaning is identical.  The inheritance relationship is avoided.


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Author Comment

by:Tom_P
ID: 6194753
Thank you Jason Clarke. That is what I thought but wasn't sure.
I think you deserve all the points, even just for the URL!
Thanks, Tom
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Expert Comment

by:jasonclarke
ID: 6194787
The GotW stuff is excellent.  I would strongly encourage you (or anyone else for that matter) to read it if you are serious about C++.

The first 47 GotWs are expanded upon in a book, Exceptional C++, which is certainly on my list of required reading for C++.  Be warned though, if you think you know C++ quite well, it might be a humbling experience (you would be in good company though, Scott Meyers said more or less the same thing).
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Author Comment

by:Tom_P
ID: 6194835
It is my plan to read all the articles. I already had a look. Yes and I do think I know C++ quite well... :) So I am in for a rough ride to prove me wrong (well hopefully not too wrong... :) ).
Anyway, thanks very much.
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