big sql self join

I have a table i need to join on itself.
the table def:
DivisionId,AssemblyNumber,SequenceNumber,ComponentPartNumber,ShipItem
all are varchar except shipitem which is a bit

basically assembly number is a partnumber and component partnumbers are partnumbers.  you add component parts under assemblynumbers
ex
assemblynumber:1
sequencenumber:1
compententpart:A
shipitem:      0
assemblynumber:1
sequencenumber:2
compententpart:B
shipitem:      0
assemblynumber:1
sequencenumber:3
compententpart:C
shipitem:      0
etc... you can also have assemblies under assemblies
assemblynumber:2
sequencenumber:1
compententpart:A
shipitem:      0
assemblynumber:2
sequencenumber:2
compententpart:1 'this the the assemble above
shipitem:      0
now your assembly 2 has a part a and a part 1 that happens to be an assembly composed of other parts.  I need a self join that will give me the records that have a ship item of 1 that starts with the main assembly and then gets all below it.  the layers could go very deep also. ex you have assembly 1 which as assembly 2 which has assembly 3 and 4 which then have more etc. if possible i would also need it to stop on the main assemblies if they are ship items.  ex assembly 1 as a part a under it and assembly 2 under it.  assembly 2 is marked as a shipitem.  it also has parts under it, but i don't care since it is marked already. any ideas?
LVL 3
jrspanoAsked:
Who is Participating?

Improve company productivity with a Business Account.Sign Up

x
 
nigelrivettConnect With a Mentor Commented:
This looks like a basic tree structure and you can probably use code that gets a tree hierarchy.

see http://www.experts-exchange.com/jsp/qShow.jsp?ta=dbgen&qid=20136561
for some code I posted earlier to get the full hierarchy.
0
 
acampomaCommented:
listening
0
 
jrspanoAuthor Commented:
is there any way to do it with out a temp table, with joins or something like that?
0
What Kind of Coding Program is Right for You?

There are many ways to learn to code these days. From coding bootcamps like Flatiron School to online courses to totally free beginner resources. The best way to learn to code depends on many factors, but the most important one is you. See what course is best for you.

 
Guy Hengel [angelIII / a3]Billing EngineerCommented:
Unfortunately, SQL Server does not give you this option, while ORACLE does :-(
0
 
nigelrivettCommented:
Only if you want to limit the number of levels - you basically need one join per level.
0
 
jrspanoAuthor Commented:
ok thanks i'll use the temp table idea here is the code from the other post if someone else should buy this question they can see it

by nigelrivett:
Your relationship structure should be maintained by a table with

parent child

so you would have

0  01
0  02
0  03
0  04
01 011
01 012

For this structure a query that will get the entire structure is (for sql server - can be adapted for
others).
From an answer I have given previously. You can adapt this to give your solution.


General way to handle trees. Fails when the squence varchar length is exceeded - in this case 100 levels.

Problems for more than 800.

create table #z (id int, name varchar(20), threadID int null)
insert #z select   1,  'foo', null
insert #z select     2,  'foo2',   null
insert #z select     3,  'foo2a',      2
insert #z select     4,  'foo2b',      2
insert #z select     5,  'foo3',   null
insert #z select     6,  'foo3b',      5
insert #z select     7,  'foo3ba',     6
insert #z select     8,  'foo4',   null
insert #z select     9,  'fooa',       1
insert #z select    10,  'foo2ba',     4

drop table #a
go
create table #a (id int, sequence varchar(1000), levelNo int)
insert #a select id, right(space(10) + convert(varchar(10),id),10), 1 from #z where threadid is null
declare @i int
select @i = 0
while @@rowcount > 0
begin
select @i = @i + 1
insert #a
select #z.id, sequence + right(space(10) + convert(varchar(10),#z.id),10), @i + 1
from #z, #a
where #a.levelNo = @i
and #z.threadID = #a.id
end

select #z.name
from #a, #z
where #a.id = #z.id
order by sequence
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.