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Return to start function?

Posted on 2001-06-21
4
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Last Modified: 2013-11-20
Hi experts,

I call function A(), A() calls B(),...., calls Z().
If something wrong in function Z(), program will be stoped by exit(0) in the function Z().
Now, I want it goes back to function A(), instead of stoped, if anything wrong in function Z().
I know we can do that by 'return' from z() to Y()....to A() but need hard work!

Any good suggestions?
0
Comment
Question by:learn
  • 2
4 Comments
 
LVL 12

Accepted Solution

by:
migel earned 60 total points
ID: 6214017
Hi!
use exception mechanism
that is:
A()
{
try
{
B();
}
catch(int)
{
// something wrong in the call chain
}
}

B()
{
Z();
}

Z()
{
if (error condition)
 throw 5; // generate exception;
}
0
 
LVL 3

Expert Comment

by:cypherljk
ID: 6214019
learn,
  I don't know what you mean by 'something goes wrong' but take a look at using 'try' and 'catch' blocks.  If an error or exception is caught it will be passed back up the calling stack.  the calling stack is a list of the functions that are currently executing. For example if A(), A() calls B(),...., calls Z() and exception 1 happens in z() if your catch block in in z catchs errors/exceptions of type 1 you could call a() from there OR you could have the catch in a(). You'll need to look up exceptions handling as there are many ways you can handle and pass exceptions and errors.

My 2 cents...
0
 

Author Comment

by:learn
ID: 6214640
Thanks a lot, that works great.

Thanks to all experts as well.....
0
 
LVL 3

Expert Comment

by:cypherljk
ID: 6216884
close the reference to this ? in the c++ section

my 2 cents...
0

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