Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people, just like you, are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
Solved

com.oreilly.servlet question

Posted on 2001-06-22
6
215 Views
Last Modified: 2010-04-16
Hi everybody!

I am using the package com.oreilly.servlet for uploading files to my server.

What I wanted to do is upload an image that has a name but I want to save it in my server with another name.

I want to save the image:

client:  c:/images/image.jpg

and overwrite this image in the server in

server: c:/server/images/serverimage.jpg

is there any easy way to do it?

Thanks!

Pablo
0
Comment
Question by:pablete
  • 2
  • 2
  • 2
6 Comments
 
LVL 3

Expert Comment

by:jerelw
ID: 6219483
1. create your File with the name you want
2. get your InputStream
3. write the stream to the File

0
 
LVL 1

Expert Comment

by:goldwarlock
ID: 6219566
The name of 1st file has no connection with 2nd
All you need is to handle the Streams!
So jerelw is right
0
 
LVL 1

Expert Comment

by:goldwarlock
ID: 6219614
btw: visit my site
www.xanga.com/goldwarlock
0
Free Tool: ZipGrep

ZipGrep is a utility that can list and search zip (.war, .ear, .jar, etc) archives for text patterns, without the need to extract the archive's contents.

One of a set of tools we're offering as a way to say thank you for being a part of the community.

 

Author Comment

by:pablete
ID: 6223867
Sorry about my lack of knowledge, but I don't know how to do that.

I am using the object MultipartRequest:

MultipartRequest(HttpServletRequest request ,String filePath , int size).

Constructor for class com.oreilly.servlet.MultipartRequest
Constructs a new MultipartRequest to handle the specified request, saving any uploaded files to the given directory, and limiting the upload size to the specified length.

Just creating the object the file is written, I don't get any parameters or anything, so I don't know how to handle the file.

Thanks again,

Pablo




0
 
LVL 3

Accepted Solution

by:
jerelw earned 200 total points
ID: 6225699
public static void writeToFile(String fileName, InputStream is) throws Exception {
    try {
     
       FileOutputStream fos    = new FileOutputStream(new File(fileName));          
       BufferedInputStream bis = new BufferedInputStream(is);          
       
       int c = 0;          
       
       while ((c = bis.read()) != -1) {              
         fos.write(c);          
      }
       fos.flush();
       fos.close();
    }
     catch(Exception e) {
       throw new Exception("Err Writing Contents: " + e);
     }    
  }

use request.getInputStream();

to get your InputStream
0
 

Author Comment

by:pablete
ID: 6226802
Cheers!

Pablo
0

Featured Post

Networking for the Cloud Era

Join Microsoft and Riverbed for a discussion and demonstration of enhancements to SteelConnect:
-One-click orchestration and cloud connectivity in Azure environments
-Tight integration of SD-WAN and WAN optimization capabilities
-Scalability and resiliency equal to a data center

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

For customizing the look of your lightweight component and making it look lucid like it was made of glass. Or: how to make your component more Apple-ish ;) This tip assumes your component to be of rectangular shape and completely opaque. (COD…
Java had always been an easily readable and understandable language.  Some relatively recent changes in the language seem to be changing this pretty fast, and anyone that had not seen any Java code for the last 5 years will possibly have issues unde…
Viewers learn how to read error messages and identify possible mistakes that could cause hours of frustration. Coding is as much about debugging your code as it is about writing it. Define Error Message: Line Numbers: Type of Error: Break Down…
Viewers will learn one way to get user input in Java. Introduce the Scanner object: Declare the variable that stores the user input: An example prompting the user for input: Methods you need to invoke in order to properly get  user input:

829 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question