Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people, just like you, are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
Solved

Need Column(1) in  ItemData(varItm)

Posted on 2001-06-27
7
838 Views
Last Modified: 2012-08-14
Hello Experts,
Can anyone help me get the second column from a 2 column List Box?

I can get the Bound column like this...

For Each varItm In Me!MyList.ItemsSelected
          strSQL = strSQL & Me!lstCustomers.ItemData(varItm)
          strSQL = strSQL & "','"
          intCount = intCount + 1
Next varItm

But how do I work Column(1) into that?

In otherwords, I would like to get the second column (the unbound column) of the 2 column list.

I tried...
Me!lstCustomers.ItemData(varItm).Column(1)
("Object Required")

and...
Me!lstCustomers.Column(1).ItemData(varItm)
("Object Required")

and...
Me!lstCustomers.ItemData(varItm, 1)
("Wrong Number of Arguments")

and...
Me!lstStateAreaCode.Column(1)
(returns "")

Any ideas?

Thanks,
Mac
0
Comment
Question by:MacRena
  • 4
  • 3
7 Comments
 
LVL 54

Expert Comment

by:nico5038
ID: 6232079
Did you try: varItm.column(1) ?

Nic;o)
0
 
LVL 4

Author Comment

by:MacRena
ID: 6232123
Hi Nico,

I'm not sure what you are suggesting...

I already tried...
Me!lstCustomers.ItemData(varItm).Column(1)
("Object Required")

do you mean? ...
Me!lstStateAreaCode.varItm.Column(1)
("Object doesn't support this property or method"

Can you please add a little more of the line so I can tell what your syntax would be?

Thanks,
Mac

0
 
LVL 4

Author Comment

by:MacRena
ID: 6232145
Oops, I'm getting 2 rountines mixed up...

Don't worry that there seems to be a problem with the name of the list box.  There is one called lstCustomers, and one called lstStateAreaCode.  They both are trying to do the same thing.

Mac

0
The Eight Noble Truths of Backup and Recovery

How can IT departments tackle the challenges of a Big Data world? This white paper provides a roadmap to success and helps companies ensure that all their data is safe and secure, no matter if it resides on-premise with physical or virtual machines or in the cloud.

 
LVL 54

Expert Comment

by:nico5038
ID: 6232191
I'm referring to varItm as a listboxitem "on itself".
The [for each] should offer the Item "itself" with the columns as property.
Got the idea?

Nic;o)
0
 
LVL 4

Author Comment

by:MacRena
ID: 6232287
Hmmm,  I'm sorry, Nico.  I'm not sure I follow you...

This is what exposes the VALUE of the Bound Column, or Column(0), in a loop through the selected List Items

Me!lstStateAreaCode.ItemData(varItm)

Now, you suggest that varItm is a "ListBoxItem" unto itself.
You also suggest that varItm exposes it's Columns property, and that I should be able to return the values of those Colunms.

Help says "The ItemData property returns the data in the bound column for the specified row"  That would be varItm, wouldn't it?  I mean, varItm would be the DATA in the Bound Column(0) that was returned by .ItemData().
I'm not understanding how you suggest that I would expose the DATA in the Column(1) from that.

Would you please write me a statement illustrating what your syntax might look like?

Thank you very much.
Mac


0
 
LVL 54

Accepted Solution

by:
nico5038 earned 50 total points
ID: 6232409
Hi,

This will work:

For Each varItm In Me!MyList.ItemsSelected
         strSQL = strSQL & Me!lstCustomers.Column(1, varItm)
         strSQL = strSQL & "','"
         intCount = intCount + 1
Next varItm

(Was too much on the "Object" focussed, without testing....)

Nic;o)
0
 
LVL 4

Author Comment

by:MacRena
ID: 6232510
Hello Nico,
Yes, that was perfect.  Thanks so much - Again!
Mac
0

Featured Post

The Eight Noble Truths of Backup and Recovery

How can IT departments tackle the challenges of a Big Data world? This white paper provides a roadmap to success and helps companies ensure that all their data is safe and secure, no matter if it resides on-premise with physical or virtual machines or in the cloud.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Experts-Exchange is a great place to come for help with solutions for your database issues, and many problems are resolved within minutes of being posted.  Others take a little more time and effort and often providing a sample database is very helpf…
Introduction The Visual Basic for Applications (VBA) language is at the heart of every application that you write. It is your key to taking Access beyond the world of wizards into a world where anything is possible. This article introduces you to…
Show developers how to use a criteria form to limit the data that appears on an Access report. It is a common requirement that users can specify the criteria for a report at runtime. The easiest way to accomplish this is using a criteria form that a…
In Microsoft Access, learn how to use Dlookup and other domain aggregate functions and one method of specifying a string value within a string. Specify the first argument, which is the expression to be returned: Specify the second argument, which …

829 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question