Go Premium for a chance to win a PS4. Enter to Win

x
?
Solved

finding the number of arguments passed in through the command prompt

Posted on 2001-07-05
1
Medium Priority
?
222 Views
Last Modified: 2011-09-20
How Do I get the Number of total arguments that is passed in at the command prompt.

example..

c:\java javaprogram first second third

I want it to return in this example 3 because there are three arguments.

Thank You.
0
Comment
Question by:selhamawy
1 Comment
 
LVL 5

Accepted Solution

by:
mattyk earned 200 total points
ID: 6257661
   public static void main (String args[]) {
        System.out.println(args.length);
    }

should do the trick


basically args.length is what you are looking for

-matty
0

Featured Post

Technology Partners: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

An old method to applying the Singleton pattern in your Java code is to check if a static instance, defined in the same class that needs to be instantiated once and only once, is null and then create a new instance; otherwise, the pre-existing insta…
Go is an acronym of golang, is a programming language developed Google in 2007. Go is a new language that is mostly in the C family, with significant input from Pascal/Modula/Oberon family. Hence Go arisen as low-level language with fast compilation…
The viewer will learn how to implement Singleton Design Pattern in Java.
How to fix incompatible JVM issue while installing Eclipse While installing Eclipse in windows, got one error like above and unable to proceed with the installation. This video describes how to successfully install Eclipse. How to solve incompa…
Suggested Courses

877 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question