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Pass last filename from FTP ls to variable

Posted on 2001-07-07
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Last Modified: 2013-12-26
How best to pass the last filename in a list from a FTP session to a variable in a shell script?

Here's what I have done -the solution works, however maybe could be improved.
Run main.sh which calls get-file-list.sh.      (.netrc is populated appropriately)

Contents of get-file-list.sh:
ftp whatever.com <<EOT
cd new-files
ls
quit
EOT

Contents of main.sh
./get-file-list.sh >current-list.txt
tail -1current-list.txt >current-last-file.txt
awk '{print $9}'current-last-file.txt


Thanks!

Roger

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Question by:dsitech
  • 5
6 Comments
 

Author Comment

by:dsitech
ID: 6261609
Actually, I just have the result printing to the screen in the above example - still need to pass that to a variable. After that, I would use the variable to actually get the file.

Roger
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Accepted Solution

by:
jkr earned 180 total points
ID: 6261762
If the file just contained the filenames line by line, you could do that like

export FILELIST=`cat current-list.txt`
export LASTENTRY
for FILEENTRY in $FILELIST; do
LASTFILE = FILEENTRY
done

After the loop, 'LASTENTRY' will hold the last file's name.
0
 

Author Comment

by:dsitech
ID: 6262095
Thanks,

FILEENTRY & LAST ENTRY are built in variables?

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Author Comment

by:dsitech
ID: 6262100
export is new for me. I looked in "Unix in a Nutshell" and I see that that is how to get a variable to be available to other scripts called by the master script.

I don't quite see how LAST ENTRY gets the value that appears to go into LASTFILE. Could you let me know how that works?

0
 

Author Comment

by:dsitech
ID: 6262135
Thanks jkr.

I worked with it a bit and have functional code here:

#/bin/sh
./ftp-whatever-list.sh >whatever_list.txt
export file_list=`cat whatever_list.txt`
export last_file
for file_entry in $file_list; do
last_file=$file_entry
done
echo $last_file > last_file.txt
cat last_file.txt     # this is to prove that I can write a log file

I appreciate the example and opportunity to learn a new concept.

Roger
0
 

Author Comment

by:dsitech
ID: 6262140
Even better (skip the file listing file):

#/bin/sh
export file_list=`./ftp-whatever-list.sh`
export last_file
for file_entry in $file_list; do
last_file=$file_entry
done
echo $last_file > last_file.txt
cat last_file.txt


Thanks again,

Roger
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