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how to auto upload file through web in iis

<form action=/script/uploadfile.asp ENCTYPE="multipart/form-data"
           METHOD=POST>
<input type=file name="filename">
</form>
I want to set file value by programing instead of manual selection.
but the inputfileelement.value is readonly
0
gutian
Asked:
gutian
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1 Solution
 
EpsylonCommented:
It's read-only for security reasons...
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gutianAuthor Commented:
I know it is read-only for reason ,I just want to know do it by any ways.
If I post the file with Sendrequestex,how can I do .
Thanks
0
 
EpsylonCommented:
Try the http component of the Indy's:

http://www.nevrona.com/Indy/Download.html
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EpsylonCommented:
Then tru this:


procedure TForm1.Button1Click(Sender: TObject);
var
  Request       : TMemoryStream;
  FileData      : TMemoryStream;
  Response      : TStringStream;
  tempArray     : array[0..10000] of char;
  tempString    : String;
  strFileSize   : String;
  InFile        : String;
const
  NewLine = chr(13) + chr(10);
begin
  Screen.Cursor := crHourGlass;

  InFile := 'c:\test.zip';

  // Set the properties for HTTP
  HTTP.ProtocolVersion                := pv1_1;
  HTTP.Request.Username               := '';
  HTTP.Request.Password               := '';
  HTTP.Request.ProxyServer            := '';
  HTTP.Request.ProxyPort              := 80;
  http.Request.ContentEncoding        := 'multipart/form-data';

  try

    // create streams
    Response  := TStringStream.Create('');
    Request   := TMemoryStream.Create;
    FileData  := TMemoryStream.Create;

    // load file data
    FileData.LoadFromFile( InFile );
    FileData.Seek( 0, soFromBeginning );
    // copy form data
    TempString := '';
    TempString := TempString + '-----------------------------7d18914904ee' + NewLine;
    TempString := TempString + 'Content-Disposition: form-data; name="UserName"' + NewLine;
    TempString := TempString + '' + NewLine;
    TempString := TempString + edUserName.text + NewLine;
    TempString := TempString + '-----------------------------7d18914904ee' + NewLine;
    TempString := TempString + 'Content-Disposition: form-data; name="PassWord"' + NewLine;
    TempString := TempString + '' + NewLine;
    TempString := TempString + edPassWord.text + NewLine;
    TempString := TempString + '-----------------------------7d18914904ee' + NewLine;
    TempString := TempString + 'Content-Disposition: form-data; name="FileSize"' + NewLine;
    TempString := TempString + '' + NewLine;
    TempString := TempString + '1234567' + NewLine;
    TempString := TempString + '-----------------------------7d18914904ee' + NewLine;
    TempString := TempString + 'Content-Disposition: form-data; name="DataFileName"; filename="' + InFile + '"' + NewLine;
    TempString := TempString + 'Content-Type: application/octet-stream' + NewLine;
    TempString := TempString + '' + NewLine;

    // Add data to post
    FillChar( temparray, SizeOf( temparray ), #0 );
    strpcopy( temparray, tempstring );
    Request.Write( temparray, length(tempstring) );
    Request.Seek( 0, soFromEnd );
    Request.CopyFrom( FileData, FileData.Size );

    // copy form data
    TempString := '';
    TempString := TempString + '' + NewLine;
    TempString := TempString + '-----------------------------7d18914904ee' + NewLine;
    TempString := TempString + 'Content-Disposition: form-data; name="Submit"' + NewLine;
    TempString := TempString + '' + NewLine;
    TempString := TempString + 'Submit' + NewLine;
    TempString := TempString + '-----------------------------7d18914904ee--'  + NewLine;
    // Add data to post
    FillChar( temparray, SizeOf( temparray ), #0 );
    strpcopy( temparray, tempstring );
    Request.Write( temparray, length(tempstring) );

    // post file
    try
      HTTP.Post( edUrl.Text, Request, Response);
    except
      showmessage( "Failed!")
    end;

    // write out debug text
    memo1.lines.Add('===[TForm1.Post - Response.DataString]=================');
    memo1.Lines.add( Response.DataString );

  finally
    Response.Free;
    Request.Free;
    FileData.Free;
    Screen.Cursor := crDefault;
  end;
end;
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gutianAuthor Commented:
thanks.BTW I want to build it in a dlls,how can I do.
I have build a dlls,but when I close main form,an error
show
0
 
EpsylonCommented:
What error? Closing the main form of the DLL?
Showing some code could help...
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gutianAuthor Commented:
function PostData(hHandle:THandle;vUrl,vFileName,SavePath:string):Boolean;external 'uprequest.dll'

this is the call
if PostData(application.Handle,Url,Filename,Path) then
    showmessage('very good');

when I close the main form ,it tell me
project ..\dlls\dllcall,exe raised too many consecutive execptions:'access violation at 0x343343:read of address 0x00ea25f0'.process stopped use step or run to continue
0
 
EpsylonCommented:
Do you know about the limitation when using strings as parameter in dll functions?

  Important note about DLL memory management: ShareMem must be the
  first unit in your library's USES clause AND your project's (select
  Project-View Source) USES clause if your DLL exports any procedures or
  functions that pass strings as parameters or function results. This
  applies to all strings passed to and from your DLL--even those that
  are nested in records and classes. ShareMem is the interface unit to
  the BORLNDMM.DLL shared memory manager, which must be deployed along
  with your DLL. To avoid using BORLNDMM.DLL, pass string information
  using PChar or ShortString parameters.


I don't know if this is causing the exceptions. I need more info...
0
 
gutianAuthor Commented:
thanks for your kind help,I have resoled the problem.
0
 
EpsylonCommented:
Alright then. Thanks for the points.
0

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