JavaScript Expression

function isIP (s) {
     reIP = /^(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})$/
     if (reIP.test(s) &&
          (Number(RegExp.$1) < 256) &&
          (Number(RegExp.$2) < 256) &&
          (Number(RegExp.$3) < 256) &&
          (Number(RegExp.$4) < 256))
          return true;
     return false;
}

I don't know why not 192.168.x.x, is it is particular to u required. actually i don't know how will the ip address format. tell me details.


   

Senthil
I don't think regular expression can cover all situation
here is a example of RE for you reference:

ipPattern = /^(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})$/;
you should add some more script for the special 0.0.0.0 or 255.255.255.255 or any number which is more than 255....
 
mimi

if this case, ip address x.x.x.x

and each should not be greater than 255, as such there no format.if u put 192.256.245,.2 it will convert it into
192.0.245,.2  

so here is the validation

 <script language="JavaScript">
       function validateform()
        {
       var i    
          var str = document.Form1.USER_NAME.value      
       var test = str.split('.',4)
       for( i=0; i <= test.length ; i++){
         if (test[i].length > 3){
         alert("should not be more than 3 digit")
         return false
       }
     }
 </script>

I am blocking the question so that u can reject if u are not satify with my answer.

Maybe not as neat as the others but working as you asked for, including the IPs you mentioned and a check to see that it isn't a mask (255).

<SCRIPT language='javascript'>

function valIP(IPno)  
{
flag=true;
parts=IPno.split(".");
if (parts[0] == 10)
 {
  flag=false;
 }
if ((parts[0] == 192) && (parts[1]==168 ))
 {
  flag=false;
 }
for (a=0;a<parts.length;a++)
 {
  if ( (parts[a].length > 3) || (parts[a] > 254) )
   {
    flag=false;
   }
 }
if (!flag)
 {
  document.write("Error!");
 }
}
</script>

you call it using valIP(x.x.x.x);

I think djokov's answer is the most correct...

Hi djokov,
I have the expression like this
((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])\\."
                    + "((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])\\.((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])\\."
                    + "((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])

but i should not allow "10.x.x.x" and "192.168.x.x" Ip Address can you pls tell me how to do this.
Thanks,
Senthil

Hi djokov,
I have the expression like this
((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])\\."
                    + "((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])\\.((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])\\."
                    + "((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])

but i should not allow "10.x.x.x" and "192.168.x.x" Ip Address can you pls tell me how to do this.
Thanks,
Senthil

Hi djokov,
I have the expression like this
((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])\\."
                   + "((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])\\.((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])\\."
                   + "((2[0-4][0-9])|(2[0-5][0-5])|(1[0-9][0-9])|([1-9][0-9])|[0-9])

but i should not allow "10.x.x.x" and "192.168.x.x" Ip Address can you pls tell me how to do this.
Thanks,
Senthil

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Moondancer
Moderator @ Experts Exchange

It is time to clean this abandoned question up.  

I am putting it on a clean up list for CS.

<recommendation>
points to djokov

</recommendation>

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please leave a comment for the mods.

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per recommendation

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