Want to protect your cyber security and still get fast solutions? Ask a secure question today.Go Premium

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 316
  • Last Modified:

uploading binary files in jsp

How i do i upload binary files on to the server using an html form ? Could anybody provide me with the source for this ? Thanx in advance..............
0
nitin_bahri
Asked:
nitin_bahri
  • 6
  • 3
1 Solution
 
SendohCommented:
hi !!
check out this site for the uploa servlet...

http://www.servlets.com/cos/index.html

hope it helps. :)
0
 
anhphuongnnCommented:
Hi nitin_bahri,

This simple is tested.
Wrote by servlet.
File will be upload into c:\Temp folder

"UploadFile.html"

<html>
<body bgcolor="#ffffff">
<TABLE align=left border=0 cellPadding=0 cellSpacing=0 width=785>

    <TR>
        <TD colSpan=3></TD>
    </TR></TR>
    <TR>
        <TD></TD>
        <TD valign="top">
      <!-- Begin Contents -->
      <FORM action="http://localhost:8080/examples/servlet/UploadTextFile" method=post       ENCTYPE="multipart/form-data">
<p valign=center><h2><FONT color=#666699 face=".vnTime" size=6>Upload Files</FONT></h2></p>
<TABLE border=0 cellPadding=0 cellSpacing=0>
    <TR>
        <TD><INPUT id=file name="filename" type=file ></TD>
      </TR>
    <TR>
        <TD><INPUT id=button1 name=button1 type=submit value=Upload></TD>
    </TR>
</TABLE>
</FORM>
      <!-- End Contents -->
      </TD>
        <TD></TD></TR>
    <TR>
        <TD rowSpan=2></TD>
        <TD></TD>
        <TD></TD></TR></TABLE>

</body></HTML>


Java servlet code.

UploadTextFile.java

import java.io.*;
import java.util.*;
import javax.servlet.*;
import javax.servlet.http.*;

public class UploadTextFile extends HttpServlet {

      public void init(ServletConfig config)throws ServletException  {
       super.init(config);
      }

   public void service(HttpServletRequest request,HttpServletResponse response)
                                throws ServletException, IOException {
      String _fileName = null;
      response.setContentType("text/html");
      PrintWriter out = response.getWriter();
      out.println("<html><body>");

      if (request.getMethod().equals("POST")
            && request.getContentType().startsWith("multipart/form-data"))
            {
            int index = request.getContentType().indexOf("boundary=");
            if (index < 0) {
                   out.println("can't find boundary type");
            return;
            }

            String boundary = request.getContentType().substring(index+9);
            ServletInputStream instream = request.getInputStream();
            byte[] tmpbuffer = new byte[8600];
            int length=0;
            String inputLine=null;
            boolean moreData=true;

         //Skip until form data is reached
       length = instream.readLine(tmpbuffer,0, tmpbuffer.length);
       inputLine = new String (tmpbuffer, 0,length);

       while(inputLine.indexOf(boundary)>0 && moreData) {
         length = instream.readLine(tmpbuffer,0,tmpbuffer.length);
         inputLine = new String (tmpbuffer,0,length);

         if(length<0)
             moreData=false;

       }

               if(moreData) {
                  //cut once boundary
                  if(inputLine.indexOf("filename") >=0) {
                        int startindex=inputLine.lastIndexOf("filename");
                        _fileName = inputLine.substring(startindex+10, inputLine.indexOf("\"",startindex+11)) ;
                        _fileName = _fileName.substring(_fileName.lastIndexOf("\\")+1,_fileName.length());
                        //read content text
                        length = instream.readLine(tmpbuffer,0,tmpbuffer.length);
                        inputLine = new String (tmpbuffer,0,length);

                  }

         }//more data

         byte fileBytes[]=new byte[50000];
         int offset=0;


         if (moreData)
         try{

           while(moreData) {
             length = instream.readLine(tmpbuffer,0,tmpbuffer.length);
             inputLine = new String (tmpbuffer,0, length);
                  if(length>0 && (inputLine.indexOf(boundary) <0)){
                     System.arraycopy(tmpbuffer,0,fileBytes,offset,length);
               offset+=length;
            }else
                   moreData = false;
           }

        }catch (IOException ex){
                out.println("IOexcepton: " + ex.getMessage());
        };
       byte realFileBytes[]=new byte[offset-2];
       for(int i=0;i<offset-2;i++) {
            realFileBytes[i] = fileBytes[i];

        }

            //create file
            FileOutputStream       file_out        = null;
            File                         file_outName = null;

            try
            {

                  file_outName = new File ("c:\\Temp" + file_outName.separator + _fileName);
                  file_out = new FileOutputStream (file_outName);
                  file_out.write (realFileBytes);

                  file_out.close();
                  //response.sendRedirect("AddListUpload.Html");
                  out.println("<font color =red>Upload OK</font>");
            }
            catch (Exception      ex)
            {
                   out.println("Error when create");
            }
            //end create file

     }//end while

     out.println("</body></html>");
     out.close();
  }
}



PhuongNguyen
0
 
nitin_bahriAuthor Commented:
Hi PhuongNguyen,
                  Thanx...The code works fine for files of size upto 30kb. But whenever i try to upload a file, say of about 50kb or more i get an error msg which goes something like this:

java.lang.ArrayIndexOutOfBoundsException
     at java.lang.System.arraycopy(Native Method)
     at UploadTextFile.service(UploadTextFile.java:73)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
     at allaire.jrun.servlet.JRunSE.service(../servlet/JRunSE.java:1416)
     at allaire.jrun.session.JRunSessionService.service(../session/JRunSessionService.java:1082)
     at allaire.jrun.servlet.JRunSE.runServlet(../servlet/JRunSE.java:1270)
     at allaire.jrun.servlet.JRunNamedDispatcher.forward(../servlet/JRunNamedDispatcher.java:39)
     at allaire.jrun.servlet.Invoker.service(../servlet/Invoker.java:84)
     at allaire.jrun.servlet.JRunSE.service(../servlet/JRunSE.java:1416)
     at allaire.jrun.session.JRunSessionService.service(../session/JRunSessionService.java:1082)
     at allaire.jrun.servlet.JRunSE.runServlet(../servlet/JRunSE.java:1270)
     at allaire.jrun.servlet.JRunRequestDispatcher.forward(../servlet/JRunRequestDispatcher.java:89)
     at allaire.jrun.servlet.JRunSE.service(../servlet/JRunSE.java:1552)
     at allaire.jrun.servlet.JRunSE.service(../servlet/JRunSE.java:1542)
     at allaire.jrun.servlet.JvmContext.dispatch(../servlet/JvmContext.java:364)
     at allaire.jrun.http.WebEndpoint.run(../http/WebEndpoint.java:115)
     at allaire.jrun.ThreadPool.run(../ThreadPool.java:272)
     at allaire.jrun.WorkerThread.run(../WorkerThread.java:75)

Please help me on this. I want to upload images say of around 500 kb or so.
0
Concerto Cloud for Software Providers & ISVs

Can Concerto Cloud Services help you focus on evolving your application offerings, while delivering the best cloud experience to your customers? From DevOps to revenue models and customer support, the answer is yes!

Learn how Concerto can help you.

 
anhphuongnnCommented:
hi

Can you try again with tmpbuffer size > 8600
byte[] tmpbuffer = new byte[8600];

PhuongNguyen

0
 
anhphuongnnCommented:
Hi

Sorry you change in here
i'm tried this ok
byte fileBytes[]=new byte[500000];//50000];


still keep th same old code
byte[] tmpbuffer = new byte[860];



PhuongNguyen

0
 
nitin_bahriAuthor Commented:
Dear PhuongNguyen

The file upload servlet gives the message that the file has been successfully uploaded. But when i try to open the file inthe browser, its not opening. What could be the reason for this. Please let me know. thanx.......

Nitin
0
 
anhphuongnnCommented:
Hi nitin_bahri,

You insert new lines after those line in the code.
byte fileBytes[]=new byte[2048576];//50000];
int offset=0;

//Add new those lines
length = instream.readLine(tmpbuffer,0,tmpbuffer.length);
inputLine = new String (tmpbuffer,0, length);

That running well.

PhuongNguyen


0
 
anhphuongnnCommented:
Hi nitin_bahri,

You insert new lines after those line in the code.
byte fileBytes[]=new byte[2048576];//50000];
int offset=0;

//Add new those lines
length = instream.readLine(tmpbuffer,0,tmpbuffer.length);
inputLine = new String (tmpbuffer,0, length);

That running well.

PhuongNguyen


0
 
anhphuongnnCommented:
HI,

WHERE ARE YOU?

PhuongNguyen
0
 
nitin_bahriAuthor Commented:
Thanx friend
0

Featured Post

Concerto Cloud for Software Providers & ISVs

Can Concerto Cloud Services help you focus on evolving your application offerings, while delivering the best cloud experience to your customers? From DevOps to revenue models and customer support, the answer is yes!

Learn how Concerto can help you.

  • 6
  • 3
Tackle projects and never again get stuck behind a technical roadblock.
Join Now