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input type=radio question

Posted on 2001-08-04
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Medium Priority
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Last Modified: 2006-11-17
Hello

I have a field in my table that is called "template" and i have a form with 3 radio buttons.

When the form is loaded it has to check a radio button depending on the value.
When i submit the form it has to write the value into my table field "template".

The code i try to use looks like:

echo "<input type=radio value=1 name=template ".if ($row[template]==1) echo "checked".">";
echo "<input type=radio value=2 name=template ".if ($row[template]==2) echo "checked".">";
echo "<input type=radio value=3 name=template ".if ($row[template]==3) echo "checked".">";

Why does this not work:

I always get a parse error
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Question by:volvo
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3 Comments
 

Expert Comment

by:cynicz
ID: 6351968
change that to
echo "<input type=radio value=1 name=template" . ($row[template]==1) ? " checked" : "" . ">";

etc
0
 
LVL 15

Accepted Solution

by:
a.marsh earned 120 total points
ID: 6351981
Or why not make life easier and change the code to:

for($i = 1; $i < 4; $i++){
  echo "<input type=radio value=$i name=template";
  if($row[template] == $i) echo " checked";
  echo ">";
}


:o)

Ant
0
 
LVL 15

Expert Comment

by:a.marsh
ID: 6352809
Glad to have helped. :o)

Thanks for the A!

Ant
0

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