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Korn SHell script

I have a directory like.

main_dir -
contains some files. One file 'Filelist.lst' conatins the name of the files to be moved to the new directory.

I need a korn shell script to take filenames from a file.
Creat a directory with datestamp and move the files listed in file 'Filelist.lst' to the newly created directory.

Thanks
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sarika1977
Asked:
sarika1977
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1 Solution
 
sarika1977Author Commented:
directory name is
main_dir
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ahoffmannCommented:
cd main_dir
d=new_dir-`date +%Y%m%d`
mkdir $d
awk '{printf("mv %s %s\n",$0,'$d')}' Filelist.lst'|sh
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sarika1977Author Commented:
>> awk '{printf("mv %s %s\n",$0,'$d')}' Filelist.lst'|sh

This prompts the following sign(maybe secondary command prompt)
>

even if i print enter, it again prompts
>


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ahoffmannCommented:
what looks your Filelist.lst like?
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sarika1977Author Commented:
It contains two file names like

srk.sh
srkStatq.sh

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ahoffmannCommented:
cd main_dir
d=new_dir-`date +%Y%m%d`
mkdir $d
awk '{printf("mv %s %s\n",$0,'$d')}' Filelist.lst|sh

# there was a wrong ' behind the  Filelist.lst, sorry
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sarika1977Author Commented:
Now it says

mv: Insufficient arguments (1)                      
Usage: mv [-e ignore|warn|force] [-fi] f1 f2        
       mv [-e ignore|warn|force] [-fi] f1 ... fn d1  
       mv [-e ignore|warn|force] [-fi] d1 d2        

I am not much familiar with awk.
How does $0 gets mapped to filename. and why are you piping output to sh?
Thanks
0
 
sarika1977Author Commented:
Now it says

mv: Insufficient arguments (1)                      
Usage: mv [-e ignore|warn|force] [-fi] f1 f2        
       mv [-e ignore|warn|force] [-fi] f1 ... fn d1  
       mv [-e ignore|warn|force] [-fi] d1 d2        

I am not much familiar with awk.
How does $0 gets mapped to filename. and why are you piping output to sh?
Thanks
0
 
sarika1977Author Commented:
Now it says

mv: Insufficient arguments (1)                      
Usage: mv [-e ignore|warn|force] [-fi] f1 f2        
       mv [-e ignore|warn|force] [-fi] f1 ... fn d1  
       mv [-e ignore|warn|force] [-fi] d1 d2        

I am not much familiar with awk.
How does $0 gets mapped to filename. and why are you piping output to sh?
Thanks
0
 
ahoffmannCommented:
aargh, should switch my shell ... sorry.

please replace awk line as follows

    awk '{printf("mv %s '$d'\n",$0)}' Filelist.lst|sh

> How does $0 gets mapped to filename.
awk reads the given file, each line is stored in awk variable $0.

> and why are you piping output to sh?
this little awk program generates the shell mv commands (simply call it without  |sh), these commands are piped to a shell which then executes them.
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sarika1977Author Commented:
It works great. Thank you very much.
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