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php and mysql query

Posted on 2001-08-21
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Last Modified: 2008-02-01
I want to know how do get the results from this query

mysql> SELECT PERIOD_DIFF(20010101,20010110) as days;

to a variable in my php script

I am have no problems connecting to my database or query tables in my database but i don't know how to the the results of this query to a variable in my script.

This is what I have so far:
<?PHP
$login="mylogin";
$pass ="mydbpass";
$db=mysql_connect("localhost",$login,$pass);
mysql_select_db("mydb",$db);
$sql = "SELECT PERIOD_DIFF(20010101,20010110) as days";
$result=MySQL_query($sql,$db);

//This is where I am stuck
$diff_days = //result from mysql query
echo "$diff_days<br>";

?>";


Please Help!
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Comment
Question by:onestar
1 Comment
 

Accepted Solution

by:
KestasS earned 50 total points
ID: 6410005
Just use function mysql_fetch_array (more info in www.zend.com)

For example you can fill select options:
<select name="cmbOwner">
    <? while ($myrow = mysql_fetch_array($rstOWNER)) {  
           echo"<option>";
          echo $myrow["name"];
       echo "</option>"  ;}   ?>
    </select>


In your case it will be :
<? echo $myrow["days"]; ?>

Good luck !

Kestas

0

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