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Evaluating a string into a decimal type

Posted on 2001-09-03
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Last Modified: 2012-06-27
This is my problem:

Server: Msg 8164, Level 16, State 1, Procedure proc_Evaluate_Formula, Line 73
An INSERT EXEC statement cannot be nested.

I have a procedure that calls another stored procedure.  In the first procedure, I have an INSERT EXEC statement.  In the seconde procedure, I also have an INSERT EXEC statement.  Now, this is not allowed.  Is there any other way to get around this?


More Info:

In the second procedure, I use INSERT EXEC to evaluate a string that looks like this 'SELECT 100 + 200 + 300' to a decimal type in the table where I INSERT EXEC.  This is done to evaluate '100 + 200 + 300'.  Is there any other way to evaluate a string that looks similar to a formula into it's decimal value?
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Question by:yurrea
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5 Comments
 
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Accepted Solution

by:
george74 earned 200 total points
ID: 6450515
yurrea,

how about this:

set nocount on
declare @f varchar(200)
declare @sql varchar(200)
declare @i decimal

set @f = '100 + 200 + 300'

set @sql = 'insert into #t1 select cast((' + @f + ') as decimal) as result'

create table #t1(result decimal)
exec (@sql)
select @i = (select top 1 result from #t1)
drop table #t1

print @i

(in this example i didn't deal with error handling/checking if all characters in @f can be converted to decimal / ie. if @f contains letters, etc.)

Cheers.
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Author Comment

by:yurrea
ID: 6451865
Hey george74!

I'm a little curious about the code that you gave.  Why is it that when you do it your way (executing a dynamic query), it works.  But when I try to play around with it - I hard-coded the dynamic query, it doesn't work? Why is that?  The '100 + 200 + 300' is not evaluated when it's hard-coded.
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Author Comment

by:yurrea
ID: 6451866
Hey don't worry, I'll accept your answer anyway. :)
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LVL 1

Expert Comment

by:george74
ID: 6452937
hi yurrea,

thanks for the points. sorry, i was occupied by development so couldn't check here before.
i don't know what you do wrong when hard-coding (unless you enclose the formula between quotes), because the code below works as well.

set nocount on
declare @i decimal
create table #t1(result decimal)
--exec (@sql)
exec ('insert into #t1 select 100+200+300  as result')
select @i = (select top 1 result from #t1)
drop table #t1

print @i

this would not work:
exec ('insert into #t1 select '100+200+300' as result')
nor this
exec ('insert into #t1 select cast('100+200+300' as decimal) as result')

but anyway, i guess you need a general formula evaluator, that takes the formula as a parameter, right?

cheers,
george
0
 

Author Comment

by:yurrea
ID: 6454998
you're right george!
thanks again.

Yvann
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