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Search a variable and put in a array.... Help !!!!!

Posted on 2001-09-12
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Last Modified: 2013-12-25
Dear everyone ,

I have a variable=

$file = qq!print "Content-type: text/html\n\n";if ($ENV{'QUERY_STRING'} =~ /^album=(\S+);image=(\d+);whatsnew$/) {$dir = $1;$si = $2;$no = $2;!;


Now what i want is the code which scans the whole $file for variables (eg. $no , $dir). It should ignore Numbers (eg $1,$2) and then add their name to a array.

It should not repeat the same variable twice
 in the array.

Thus the array should read something like this -

@array = ("no","si","dir","and so on");

Please help ASAP...

Anant
0
Comment
Question by:anant99
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7 Comments
 
LVL 6

Expert Comment

by:Jaymol
ID: 6476730
listening...
0
 
LVL 1

Author Comment

by:anant99
ID: 6477193
I think some one can modify this :-

while ($file) {
if (/\$(\w+)/) {
push(@array,$1);
}

i dont know how to get it working...

Please help !!!

Anant
0
 
LVL 5

Expert Comment

by:amandeep
ID: 6477829
anant99,

Try it this way :

while ($file=~/\$(\w+)/g) {
  my $v=$1;
  push(@array,$v) unless($v=~/^\d+$/);
}

Hope this helps

Aman
:-)
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LVL 1

Author Comment

by:anant99
ID: 6478612
also can u filter out captial variables like $ENV
0
 
LVL 84

Accepted Solution

by:
ozo earned 200 total points
ID: 6486697
$file = q!print "Content-type: text/html\n\n";if($ENV{'QUERY_STRING'} =~ /^album=(\S+);image=(\d+);whatsnew$/)
{$dir = $1;$si = $2;$no = $2;!;
@array = reverse $file=~/\$([a-z]+)\b/g
0
 
LVL 51

Expert Comment

by:ahoffmann
ID: 6486698
do you mean just to extract the variable names from the string in $ENV{'QUERY_STRING'}  ?
0
 
LVL 1

Author Comment

by:anant99
ID: 6486874
Thanks !!! This is just what I wanted...
0

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