How can I get the memory size from a stl map container?

friends, please help me on the following :-

#include <map>
#include <string>
using namespace std;

typedef map<string, int> STR_MAP;

int main(int argc, char* argv[])
{
  STR_MAP strmap;
  for(int i=0; i <1000; i++) {
    strmap.insert(STR_MAP::value_type(string  
               ("something"), i));
        }

/// i would like to get the memory allocated size of this
// map container
   // mem_size(strmap) ????????/


}
pphariAsked:
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AxterConnect With a Mentor Commented:
In the following example, I reversed the map pair to <int, string>.
This allows your code to insert 1000 items.

#include <map>
#include <string>
#include <numeric>

using namespace std;

typedef map<int, string> STR_MAP;

int GetTotalSize(int Accum, pair<int, string> Cur)
{
     return Accum + sizeof(Cur.first) + Cur.second.size();
}

int main(int argc, char* argv[])
{
     STR_MAP strmap;
     for(int i=0; i <1000; i++)
     {
          strmap.insert(STR_MAP::value_type(i, string ("something")));
     }
     
     int TotalSizeOfAllItemsInContainer = accumulate(strmap.begin(),strmap.end(),0,GetTotalSize);
     int TotalQtyOfPairsInContainer = strmap.size();
     int TotalSizeOfPair = sizeof(pair<int, string>);
     
     int TotalSizeOfContainer = TotalSizeOfAllItemsInContainer +
                    (TotalQtyOfPairsInContainer * TotalSizeOfPair) +
                    sizeof(STR_MAP);
     return 0;
}

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AxterCommented:
Because std::string does not have a fix size, you would have to iterate through the list, to get the complete size.
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AxterCommented:
You can use the following method to get the accumulate() function to get the total size:

Example code:

#include <map>
#include <string>
#include <numeric>

using namespace std;

typedef map<string, int> STR_MAP;

int GetTotalSize(int Accum, pair<string, int> Cur)
{
     return Accum + Cur.first.size() + sizeof(Cur.second);
}

int main(int argc, char* argv[])
{
     STR_MAP strmap;
     for(int i=0; i <1000; i++)
     {
          strmap.insert(STR_MAP::value_type(string  
               ("something"), i));
     }

     int TotalStringSize = accumulate(strmap.begin(),strmap.end(),0,GetTotalSize);
     
     return 0;
}

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AxterCommented:
The above code will return a number of 13, because you only have one item in the container.
Even though you add this (string("something"), i) to the container a 1000 times, you still only end up with one item because the key is the string.  Since the string remains the same, you're inserting the item in the same location over and over again.
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pphariAuthor Commented:
hi axter, thanks for your great answer, infact my hash key is string only, the value of its changes all the time and container is a multimap..
once again thanks...
Hari
0
 
pphariAuthor Commented:
hi axter, thanks for your great answer, infact my hash key is string only, the value of its changes all the time and container is a multimap..
once again thanks...
Hari
0
 
pphariAuthor Commented:
hi axter, thanks for your great answer, infact my hash key is string only, the value of its changes all the time and container is a multimap..
once again thanks...
Hari
0
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