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Simple? How would I do this?

siceman105
siceman105 asked
on
Hi all,
I cant get my head round this, so hopefully somewhere here can help.

Basically I have a database, its got two tables one for users and one for documents. Now both tables have a column regarding "permissions", i.e who can view these documents.

So heres an example of the table

Userstable

username|permissions
john | commercial , finance
peter| finance

Documents Table
title | viewing
report | commercial
data | finance
proposal | commercial, finance


But my question is how do I use PHP to store these values? Ive heard something about arrays, would this apply? How do I use checkboxes (to set the values in the database) and then retrieve them?

Thanks

Siceman
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Commented:
The easiest way to solve this is not the way you are suggesting. Better is to make a third table in which you store which user is allowed to view which document. So the table has two columns: one with a userid and one with a documentid. When a user is allowed to view a document, add a record. When a user is allowed to view another document, than simply add another record.
I assume you can think of the php-code yourself?
Chad SmithSoftware Engineer
CERTIFIED EXPERT

Commented:
Here is a great how-to with code:
http://www.devshed.com/Server_Side/PHP/Cracking
Here is an easy way

Change your usertables

so

id|user | commercial | finance
123|john|1|0
124|peter|1|1

On each page have


include("logcheck.inc");
$login_id = is_logged(); //which would be function that checks if the person is logged by a cookie and returns the id on success

if($login_id){
$permission = can_view('commercial',$login_id);
}else{

include("login.html");  //not logged in so we need to go to login form
exit;

}
if(!$permission){
    echo "sorry this area denied";
    exit;
}
//commercial stuff from here

-----------------------------------------
----------------logcheck.inc-------------
function can_view($area,$id){
$query = "select user_name from user_table where $area = '1' AND id = '$id'";
$result = mysql_query($query);
$success = mysql_num_rows($result);
return $success;
}


}

function is_logged(){

//cookie check here

}
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