variable-length array?

What's wrong with this short program, and how do I make it work? (I do not want to fix/limit the size of the array to 10000.)

Thanks.
---------------
#include <stdio.h>
#include <stdlib.h>

void main(int argc, char** argv){
//  char content[10000];
  if(argc<3){
     printf("Usage: \n       sendfile number_of_bytes file_name\n");
     exit(0);
  }

  FILE* fout=fopen(argv[2],"w");
  int num=atoi(argv[1]);
int * size=(int *)malloc((size_t)num);
char content[*size];
  for(int i=0; i<num; i++)content[i]='a';
  fwrite(content,1,num,fout);
free(size);
}
anotherctoAsked:
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pagladasuConnect With a Mentor Commented:
char *content=(char *)malloc(num);
0
 
thienpnguyenCommented:
#include <stdio.h>
#include <stdlib.h>


void main(int argc, char **argv)
{
    //  char content[10000];
    if(argc < 3)
    {
        printf("Usage: \n       sendfile number_of_bytes file_name\n");
        exit(0);
    }
    FILE * fout = fopen(argv[2], "w");

    if( fout == NULL )
        return;
   
    int       num = atoi(argv[1]);
    char *content = (char *)malloc(num*sizeof(int));

    if( content == NULL )
        return;
   
    for(int i = 0; i < num; i++)
        content[i] = 'a';
    fwrite(content, 1, num, fout);

    free(content);
    fclose(fout);
}

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thienpnguyenCommented:
if you write in "pure" C, the code as following.


#include <stdio.h>
#include <stdlib.h>


void main(int argc, char **argv)
{
    FILE * fout;
    int    num, i;
    char *content;

   
    //  char content[10000];
    if(argc < 3)
    {
        printf("Usage: \n       sendfile number_of_bytes file_name\n");
        exit(0);
    }

    fout = fopen(argv[2], "w");
    if( fout == NULL )
        return;
   
    num = atoi(argv[1]);
    content = (char *)malloc(num*sizeof(int));

    if( content == NULL )
        return;
   
    for(i = 0; i < num; i++)
        content[i] = 'a';
    fwrite(content, 1, num, fout);

    free(content);
    fclose(fout);
}

0
 
anotherctoAuthor Commented:
thienpnguyen,

I'll post 50 points for you.
Thanks.
0
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