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Get image data pointed to by a Resource id

I am currently working on a gallery project.

I have written code to store clients photos in a Mysql database, which is all working okay. I want to create a thumbnail on the fly which I do with the following code :-

$def_thumb_width=100;
$def_thumb_height=75;
$thumb_image_name= "t_" . $original_image_name;

$scaling_width=$original_image_width / $def_thumb_width;
$scaling_height=$original_image_height / $def_thumb_height;
if ($scaling_width > $scaling_height)
{
$thumb_width=$original_image_width / $scaling_width;
$thumb_height=$original_image_height / $scaling_width;
}
else
{
$thumb_width=$original_image_width / $scaling_height;
$thumb_height=$original_image_height / $scaling_height;
}
$thumb_width= ceil($thumb_width);
$thumb_height= ceil($thumb_height);

$im=imagecreatefromjpeg("$original_image");
$thumb=imagecreate($thumb_width,$thumb_height);
imagecopyresized($thumb,$im,0,0,0,0,$thumb_width,$thumb_height,$original_image_width,$original_image_height)

I have used fopen to open the original file in order to get the binary for the file. To prevent writing the data out to a file and reading it back again, I need to gain access to the data. $thumb will contain the image resource, and ImageJPEG($thumb) will output the data to the screen but I want it sent to my database instead.

In short how do I access data pointed to by a resource id.

Richard Quadling

If you are storing the images in the database, then you may as well do it off line.

I use a program called ThumbsPlus on Windows. It can write to MySQL databases no problems.

But to answer your question, you can add a file name to

ImageJPEG($thumb,"/home/images/saved.jpg");

and then put that file in the database the same way you did the main image.

I cannot see a standard function to allow you to access the data directly.

BUT, what would happen if you sent the data to STDOUT (or something similar) and caught it via another program/script? No idea if possible.

Regards,

Richard Quadling.

waygood

ASKER

I did capure the data as a work around using :-

ob_start();
Imagejpeg($thumb);

$thumb_image_size=ob_get_length();
$thumb_data=addslashes(ob_get_contents());
ob_end_clean();

but fail to see why I need to output data and recapture it again through buffering of saving as a file. The data is there, I just need to access it.

P.S. I am writing this for people who are very stupid. They don't know how to deal with more than one program open at a time, let alone how to create thumbnails. I gave them Mihov's Image Resizer (freeware) and they complained when it doubled the number of images they had (extra thumbnails). Duh!

ASKER CERTIFIED SOLUTION

Richard Quadling

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