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Korn Shell Problem

Posted on 2002-03-13
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Last Modified: 2010-04-21
I have 2 simple (I think) questions:
1. I am reading in a file which has 3 words in each record. I would like to put each word in a different array e.g. word1 would be in array1 , etc. How could I do that?
2. I am displaying the first word of each record , preceed by a sequence number on the screen e.g.
 1  value1
 2  value2
 3  value3
...
I have done this with the following code:
...
set -A number 1 2 3 4 5 6 7 8 9
...
max=9
i=0
while [[ $i -lt $max ]];do
   line="${number[$i+1]} ${array1[$i]}"
   print $line
   i=$i+1
   done
...
I would like to print the sequence number without having to create the number array, but I have tried various things and nothing seems to work. How could I do that?
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Question by:jc31415
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3 Comments
 
LVL 51

Expert Comment

by:ahoffmann
Comment Utility
#! /bin/ksh
integer i = 1
cat your-file |while read array1 array2 array3 ; do
        echo $i $array2
        let i=$i+1
done
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Author Comment

by:jc31415
Comment Utility
That doesn't solve my problem. I want to move my display forward and backward based on user input. For example I want to display the first 20 entries and then based on user input shift to the next 20 entries and then either forward 20 entries or back 20 entries. So I need the values in an array.
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Accepted Solution

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ahoffmann earned 50 total points
Comment Utility
#! /bin/ksh
integer i = 1
cat your-file |while read array1[$i] array2[$i] array3[$i] ; do
   let i=$i+1
done

# do mean this?
# no all values from column 1 are in array1, column 2 in array 2, and column 3 in array3
# given an offset for example of 5, you can do:

integer i=5 # or $1 if passed in as first parameter
while [ $i -lt 5+20 ]; do
   echo ${array1[$i]}
done
# keep in mind that there is no check of index to array1
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