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Posted on 2002-03-17
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how can i convert a decimal number to a hexadecimal number.
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Expert Comment

ID: 6873674
following are my solution, if this solution not match with your question then plz. clear the question.
solution 1.
char hexaNo[10];
sprintf(hexaNo,"%x",n); // where n is Decimal no.

solution 2.
char hextable[16] = {'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
#define TOHEX(a, b)
{*b++ = hextable[a >> 4];*b++ = hextable[a&0xf];}

solution 3.

char hexatable[]={'0','1','2','3','4',
'5','6','7','8','9','A','B','C','D','E','F'};
int n;
char hexaNo[10];
scanf("%d",&n);
while(n)
{
hexaNo[i]=hexatable[n%16];
n = n/16;
}
printf("hexa no = %s",hexaNo);

0

Expert Comment

ID: 6873676
This will explains you everything...
check it out..
http://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=3209&lngWId=3
0

Expert Comment

ID: 6873682
Or....

#include <iostream.h>

void digittohex(int n){
if (n < 10)
cout << n;

else{
if (n == 10)
cout << "A";
if (n == 11)
cout << "B";
if (n == 12)
cout << "C";
if (n == 13)
cout << "D";
if (n == 14)
cout << "E";
if (n == 15)
cout << "F";
}
}

void decimaltohex(int n){

if (n >= 0 && n < 256){
digittohex(n / 16);
digittohex(n % 16);
}
}

int main(){
int n;
cin >> n;
decimaltohex(n);
cout << endl;
return 0;
}

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Accepted Solution

GEliyahu earned 50 total points
ID: 6873685
Or....

#include <iostream.h>

void digittohex(int n){
if (n < 10)
cout << n;

else{
if (n == 10)
cout << "A";
if (n == 11)
cout << "B";
if (n == 12)
cout << "C";
if (n == 13)
cout << "D";
if (n == 14)
cout << "E";
if (n == 15)
cout << "F";
}
}

void decimaltohex(int n){

if (n >= 0 && n < 256){
digittohex(n / 16);
digittohex(n % 16);
}
}

int main(){
int n;
cin >> n;
decimaltohex(n);
cout << endl;
return 0;
}

0

Expert Comment

ID: 6873714
hi GEliyahu

what u written in the last of second comment?
can i know ur mail-id plz?
0

Expert Comment

ID: 6873761
first..
ignore pls the second comment...
just reffer to the third one..

second..
what is a mail-id?
you wants my E-mail?

0

Expert Comment

ID: 6873797
yes plz.
0

Expert Comment

ID: 6873808
geliyahu@hotmail.com
0

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