Converting from decimal to hexadecimal

hi  raqadi,
following are my solution, if this solution not match with your question then plz. clear the question.
solution 1.
char hexaNo[10];
sprintf(hexaNo,"%x",n); // where n is Decimal no.

solution 2.
char hextable[16] = {'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
#define TOHEX(a, b)    
       {*b++ = hextable[a >> 4];*b++ = hextable[a&0xf];}

solution 3.

char hexatable[]={'0','1','2','3','4',
             '5','6','7','8','9','A','B','C','D','E','F'};
int n;
char hexaNo[10];
scanf("%d",&n);
while(n)
{
     hexaNo[i]=hexatable[n%16];
      n = n/16;
}
printf("hexa no = %s",hexaNo);

This will explains you everything...
check it out..
http://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=3209&lngWId=3

Or....


#include <iostream.h>


    void digittohex(int n){
    if (n < 10)
    cout << n;


        else{
        if (n == 10)
        cout << "A";
        if (n == 11)
        cout << "B";
        if (n == 12)
        cout << "C";
        if (n == 13)
        cout << "D";
        if (n == 14)
        cout << "E";
        if (n == 15)
        cout << "F";
    }
}


    void decimaltohex(int n){


        if (n >= 0 && n < 256){
        digittohex(n / 16);
        digittohex(n % 16);
    }
}


    int main(){
    int n;
    cin >> n;
    decimaltohex(n);
    cout << endl;
    return 0;
}
 

 
 
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hi GEliyahu

what u written in the last of second comment?
can i know ur mail-id plz?

first..
ignore pls the second comment...
just reffer to the third one..

second..
what is a mail-id?
you wants my E-mail?

yes plz.

geliyahu@hotmail.com