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(BCB5) TDateTime conversion

Posted on 2002-03-19
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Last Modified: 2012-06-27
Greetings,

I am looking for functions which can convert from a TDateTime to a time_t and vice versa.
Please can someone help me ?

Thanks,

Robert
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Question by:zaroblan
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6 Comments
 
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Expert Comment

by:DrDelphi
ID: 6881670
The following example converts a time_t value to a file time, using the Int32x32To64 function.

void TimetToFileTime( time_t t, LPFILETIME pft )
{
    LONGLONG ll = Int32x32To64(t, 10000000) + 116444736000000000;
    pft->dwLowDateTime = (DWORD) ll;
    pft->dwHighDateTime = ll >>32;
}
After you have obtained a file time, you can convert this value to system time using the FileTimeToSystemTime function.

Then you can use the FileDateToDateTime to get your TDateTime.




Good luck!!

         
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Author Comment

by:zaroblan
ID: 6881777
Are there no available functions to do this without needing to use three levels of indirection ?
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Accepted Solution

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LoungeLizard earned 100 total points
ID: 6882012
Well, TDateTime is effectively a double, indicating the number of days since 30/12/1899 00:00:00 and time_t is an long int that indicates the number of seconds since 1/1/1970 00:00:00 which means there is a constant difference between them. Just figure out what that is (use Excel or whatever) and use that in conversions.
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Author Comment

by:zaroblan
ID: 6882041
// According to the online help "time_t" is just a "long" which contains
// the number of seconds since 1st Jan 1970 0:00:00 GMT. And it says that
// TDateTime has a constructor which takes a double representing the number
// of days since 31st Dec 1899.

const int EpochDiff = 25569; // days between 30/12/1899 and 01/01/1970
const int SecsInDay = 86400; // number of seconds in a day

TDateTime TimeT_TDateTime(time_t Convertee)
{
  TDateTime Result(((double)Convertee) / SecsInDay + EpochDiff);
  return Result;
}

// Now to reverse this operation you can cast a TDateTime into a
// double and then apply the reverse mathematics:

time_t TDateTime_TimeT(TDateTime Convertee)
{
  time_t Result((long)((((double)Convertee) - EpochDiff) * SecsInDay));
  return Result;
}
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Expert Comment

by:LoungeLizard
ID: 6882072
Yup, that's what I meant.
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Author Comment

by:zaroblan
ID: 6882092
Thanks for the pointer in the right direction ... would have been rated as excellent if you had supplied a code sample :)
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