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escheider

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Listview Question

Hello Experts:

I have a listview that contains a list of clients.  Column 1 contains the clientid and column 2 contains the client name.

I also have a janusys grid on the form which will display a filtered invoice listing based on the client that is selected in the client listview.

I have recently added a search button to allow the user to search for an invoice, which works correctly, by displaying the invoice that was searched for in the janus grid.  However, I also want to highlight the client in the client list that the invoice corresponds to, I've tried several things with no results.

Here is what I am trying

ClientList is the Listview displaying the clients
strReturnCustomer is the clientid field Im trying to match up to column 1 in the listview

For Counter = 1 To ClientList.ListItems.Count
     If ClientList.ListItems(Counter) = strReturnCustomer Then
                ClientList.ListItems(Counter).selected= True
     End If
Next

Thanks

VB 6.0
Avatar of CodeWizrd
CodeWizrd


If you are checking on customer number, then change your if statement to:

If ClientList.ListItems(Counter).subitems(1) = strReturnCustomer Then

This way you are validating only the first column in your list box.
Avatar of escheider

ASKER

ClientList.ListItems(Counter).subitems(1) would reference the customer name, not the customer id.

oops...I typed a 1, didnt I?  Problem with coding too many languages...

Did the subitem help you match your customer id and highlight the row you wanted?

no,

ClientList.ListItems(Counter) appears to be referencing the clientid column, but ClientList.ListItems(Counter).selected= True doesn't appear to be working.  The IF statement is triggered, but the client being referenced is not highlighted.
hmmm, i put a clientlist.setfocus above the clientlist.listitems(counter) line, and it appears to work now.

Interesting...well, congrats on getting it working!
freaky...do you want the points or should I delete this question??
Since I answered the question myself, I decided to delete this question.  Thanks for your input though
ASKER CERTIFIED SOLUTION
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Netminder

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