Converting a numeric date to written english

Posted on 2002-03-22
Last Modified: 2010-04-02
Hey guys, I am writing a program that will accept a date in the MM/DD/YYYY format and return it in written english...EX: March Fifth, Two Thousand Two

I have the program working from 1990 through now, including filtering out erroneous dates...such as the 29th of February on a non-leap year.  So far I have been converting everything through a CASE SWITCH statement

EX:  CASE 1990: return "nineteen-ninety";

Here's the problem...I want this program to perform this function at least back to 1900...or earlier would be better.  I cannot figure out a way to write these year statements without typing out every single year that I want to have available.  What would be a good way of going about this?

Thanks in advance,

Question by:96gtjeff
LVL 30

Expert Comment

ID: 6890375
You could just make a string for each two digit number from 0 to 19.
Then use a dual algrithm to come up with the numbers from 20 to 99
LVL 16

Accepted Solution

Peter Kwan earned 100 total points
ID: 6890509
First, you need to define some constant "roots" (or you may say elements) for each digit except 0.

1: one
2: two, twen (<- twenty)
3: three, thir (<- thirteen, thirty)
4: four, for (<-forty)
5: five, fif (<-fifty, fifteen)
6: six
7: seven,
8: eight, eigh (<- eighty, eighteen)
9: nine
10: ten
1000: thousand
10+a (2<a<10): teen
10*a (1<a<10): ty

The parathesis with <- is/are the cases where the "root" is used.

Next, define some constant strings for the following exceptional cases:
00: hundred
11: eleven
12: twelve

Then you need to define some rules (where y=input year, and the content inside parenthesis is just for human explanation only, not for coding):

Case A)
y/100==19 (=> 9 + 10)
=> "nine" + "teen"; n=y-1900;

n==0 (=> 00)
=> "-hundred"
0<n<13 => + "-and-" + (direct translation of n)
13<=n<=19 => "-" + (translation of n-10) + (direct translation of (10+a))
2<=n<=9 && n%10==0 => "-" + (translation of n/10) + (direct translation of (10*a))
2<=n<=9 && n%10!=0 => "-" + (translation of n/10) + (direct translation of (10*a)) + "-" + (direct translation of n%10)
Case B)
y>=2000 (=> 2 * 1000)
=> "two" + "-" + "thosand" + "-" + "and-"; n=y-2000;
0<n<13 => + (direct translation of n)
13<=n<=19 => (translation of n-10) + (direct translation of (10+a))
2<=n<=9 && n%10==0 => (translation of n/10) + (direct translation of (10*a))
2<=n<=9 && n%10!=0 => (translation of n/10) + (direct translation of (10*a)) + "-" + (direct translation of n%10)

This is just a pseudocode. You need to translate to
C++ using conditionals.

Author Comment

ID: 6890513
Thank you very much...this oughta do it.
LVL 84

Expert Comment

ID: 6890517

Featured Post

Master Your Team's Linux and Cloud Stack

Come see why top tech companies like Mailchimp and Media Temple use Linux Academy to build their employee training programs.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

When writing generic code, using template meta-programming techniques, it is sometimes useful to know if a type is convertible to another type. A good example of when this might be is if you are writing diagnostic instrumentation for code to generat…
Basic understanding on "OO- Object Orientation" is needed for designing a logical solution to solve a problem. Basic OOAD is a prerequisite for a coder to ensure that they follow the basic design of OO. This would help developers to understand the b…
The viewer will learn how to pass data into a function in C++. This is one step further in using functions. Instead of only printing text onto the console, the function will be able to perform calculations with argumentents given by the user.
The viewer will be introduced to the member functions push_back and pop_back of the vector class. The video will teach the difference between the two as well as how to use each one along with its functionality.

770 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question