Solved

Color Graphics Problem

Posted on 2002-03-29
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Last Modified: 2010-03-31
Hi, say I've got an applet that displays values in an array in the form of a bar graph. Each value corresponding to a bar. How can I color one particular bar with a different color from the rest such that the one that is the largest has a different color to the other bars.

the code that displays the graphs in the array is below.
thanks...

public void displayBars (int [] data, Graphics g){
          try{

               g.setColor(Color.red);
               setBackground(Color.white);

               int largest;
               int yStart = 20;
               int yHeight = 200;
               int xStart = 20;
               int width = 30;
               int gap = 10;
               int  x = xStart;
         
               for (int count =0; count <data.length; count++){
                    g.fillRect(x, yStart + yHeight- data[count], width,data[count]);
                    g.drawString(Integer.toString(data[count]),10+x,240);
                    x = x + width + gap;    
               }//for    
          }//try
          catch(NullPointerException e){
               }//catch
     }//displayBars
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Question by:q_bic
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6 Comments
 
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Accepted Solution

by:
Venci75 earned 100 total points
ID: 6905006
You can use something like this:

public void displayBars (int [] data, Graphics g){
         try{
// Here you can define the possible colors and thir sequence
              Color[] colors = {Color.red, Color.yellow, Color.blue, Color.green};
              setBackground(Color.white);

              int largest;
              int yStart = 20;
              int yHeight = 200;
              int xStart = 20;
              int width = 30;
              int gap = 10;
              int  x = xStart;

              for (int count =0; count <data.length; count++){
                   g.setColor(colors[count%colors.length]);
                   g.fillRect(x, yStart + yHeight- data[count], width,data[count]);
                   g.drawString(Integer.toString(data[count]),10+x,240);
                   x = x + width + gap;
              }//for
         }//try
         catch(NullPointerException e){
              }//catch
    }//displayBars
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by:Moondancer
ID: 6956634
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Expert Comment

by:Venci75
ID: 6959267
<recommendation>
Venci75
</recommendation>

i believe my comment was what q_bic was looking for. I normally don't recommend myself but in this case
i believe that my post was a valid solution
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Expert Comment

by:Moondancer
ID: 6965653
Thank you, Venci75.

g_bic logged in AFTER this was posted, but has not yet responded.  

Please do update and finalize this question, g_bic.  If more is needed, please let us know.

Moondancer - EE Moderator
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Expert Comment

by:Venci75
ID: 7923899
No comment has been added lately, so it's time to clean up this TA.
I will leave a recommendation in the Cleanup topic area that this question is:
Answered by: Venci75
Please leave any comments here within the next seven days.
 
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Expert Comment

by:modulo
ID: 7978506
Finalized as proposed

modulo

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