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SQL Update table

Posted on 2002-03-30
Medium Priority
Last Modified: 2010-04-04

I'm using Dbisam components and have a question.

I have 3 fields (integer) named aField, bField, cField.
it contains numbers like
0  , 20 , 20
20 , 25 , 45
45 , 10 , 55

cField is sum of aField and bField, and aField is sum of cField in previous record.

If i will change the bField  in record1 from 20 to 25 how can i write a SQL command so the whole table will update to

0  , 25 , 25
25 , 25 , 50
50 , 10 , 60

My SQL knowledge is very small.
I have solved it until now with scrolling through the table with for i=1 to table1.recordcount and so on but its not a good solution , specially when the table will contains a lot more records.
Hope you understand my question.
Question by:InterDive
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LVL 27

Expert Comment

ID: 6908551
? in sql

update tablename
bfield = 25
where bfield = 20

if the sumfield cfield should be calculated also

update tablename
bfield = 25,
cfield = afield+25
where bfield = 20

hope this helps

meikl ;-)

LVL 10

Accepted Solution

Jacco earned 400 total points
ID: 6922605
If you want to do this without looping through the records you will need an order field (I have called it bOrder):

1, 0  , 20 , 20
2, 20 , 25 , 45
3, 45 , 10 , 55

I dont know the DbiSam SQL dialect but normal SQL dialects support the following:

1) update the table with 25

  bField = 25
  bOrder = 1

2) update all of the tables aFields and cFields

  table a
  aField = (select sum(bField) from table b where b.bOrder < a.bOrder),
  cField = (select sum(bField) from table b where b.bOrder <= a.bOrder)

* You might get NULL in sum fields though. Check DbiSam documentation if the have an IfNull function and then have something like IfNull(sum(bField), 0, sum(bField)).

Downside of this is the with a large table this can be a lengthy procedure. You can optimize it a bit using:

1) update the table with 25

  bField = :newval
  bOrder = :index

2) update all of the tables aFields and cFields

  table a
  aField = (select sum(bField) from table b where b.bOrder < a.bOrder),
  cField = (select sum(bField) from table b where b.bOrder <= a.bOrder)
  bOrder >= :index

This will be a bit quicker in most cases.

I would like to mention as well that you are storing redundant data. This get one in to trouble very easily in database design. Another way to go would be:

1, 20
2, 25
3, 10

And use the following select:

  (select sum(bField) from table b where b.bOrder < a.bOrder) as aField,
  (select sum(bField) from table c where c.bOrder <= a.bOrder) as cField
  table a
order by

This way you sums are always calculated "just in time" while selecting them. If you update one value of bField you just need to open/close the select query again.

Hope this helps,

Regards Jacco

Author Comment

ID: 6922774
Thanxs Jacco :-)

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