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how show a dialog?

Posted on 2002-04-04
Medium Priority
Last Modified: 2010-04-02
I am beginner.

I want to show a dialog box.

I want to use a DLL, and a Function.

I call the function in DLL, and it's right.

for show my dialog, i use this:

BOOL CALLBACK ReplaceDialogProc (
                    HWND hwndDlg,                       UINT uMsg,WPARAM wParam, LPARAM lParam)  

   MessageBox(NULL,"message 2 - I am in callback", "REPLACEDIALOGPROC",MB_OK);
      return TRUE;  

    case WM_COMMAND:
      switch (LOWORD(wParam))
        case IDCANCEL:
          EndDialog(hwndDlg, 0);
      return TRUE;
  return FALSE;

__declspec(dllexport) LONG  APIENTRY  SetIniValue (HWND hwnd, LPLONG lpIValue, LPSTR lpszValue) {
      (DLGPROC) ReplaceDialogProc);

     MessageBox(NULL,"message 1 - Teste da minha DLL. SetIniValue",lpszValue,MB_OK);

return 0;


it show the message 1 and message2, but don't show a dialog box.

What is it wrong?

Question by:alexBrasil
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Accepted Solution

GGRUNDY earned 210 total points
ID: 6919452
Does your dialog resource have the WS_VISIBLE bit set?

Expert Comment

ID: 6919774
Just couple questions.

Is your dialog resource located in .exe ot in .dll?  
Do you have IDD_DIALOG1 defined in any other place in your app?
LVL 49

Expert Comment

ID: 6923585
You are creating a modeless dialog.  It might be a easier for you to create a Modal dialog like this:

int nErt= ::DialogBox(
     (DLGPROC) ReplaceDialogProc);

Also you will need to remove this line:
    MessageBox(NULL,"message 2 ... etc...
or move it into the WM_INITDIALOG case handler because otherwise, it will be executed on each message to the dialog.

But also be certain that yjr resource for the dialog is in the same module as the one represented by g_hInst.

-- Dan

Author Comment

ID: 6925460
Thank you.

sorry for i am beginner..

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