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Template in template

Posted on 2002-04-08
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Hi, I've run into a Visual C++ 6.0 compiler problem, that I'm not able to workaround anymore.

Using STL, an example of the problem is having a vector of lists:

std::vector<std::list<int>>

That's too much for the compiler. My easy workaround was to do a typedef std::list<int> IntList, and then compile:

std::vector<IntList>

However, I'm now making my code more general using templates. So the int in the example has turned into SomeType:

template<class SomeType>
[...]
std::vector<std::list<SomeType>>

and now my typedef trick doesn't work anymore...

How do I solve this problem? Or who knows a workaround that honors the generalization purpose (obviously I don't want to make implementations for each of the SomeType types)?

TIA
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Question by:vendrig
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jkr earned 600 total points
ID: 6925583
Make it read

std::vector<std::list<int>

Note the blank. The compiler misinterprets that as the ">>" operator.
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by:jkr
ID: 6925592
BTW - this behaviour is called the "Max Munch" principle, see also http://www.gotw.ca/gotw/078.htm ("Who Is Max Munch, and What's He Doing In My C++ Compiler?"), where your problem  is described in detail...
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by:vendrig
ID: 6925626
Thank you for your quick response:-)
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