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MySQL and PHP question....

I am a complete novice at MySQl, and really all I want to do is:

-> Connect to the db server.
-> Select a db.
-> Select a message to print to the user based on an id supplied to the script via the query string.
ie /script.php?id=1 .

I have set up a MySQL table called 'txts', and this table has three fields: 'id', 'heading', and 'message'.


Firstly, I want to display a page which lists all the messages available, in a table like this:

-------------------------------------
| Message Heading (field 'heading') |
-------------------------------------
| The actual message |
| (field 'message') |
-------------------------------------
| A link to another page giving the |
| message id via the query string |
| (using the 'id' field) |
-------------------------------------

Then, on the next page, I would like to be able to put the message into a variable ($message) which
I can use later on.... the message will be selected from the table using the ?id= parameter to get the
right message.

I know that this is a lot to ask, but can anyone give advice on how to do this. I will be extremely
grateful for any help at all.

Thanks,
Nick!
0
Nick500000
Asked:
Nick500000
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1 Solution
 
lokeshvCommented:
connect to db server

$conn=mysql_pconnect("host","user","password");

mysql_select_db("database_name");

$query="selct ur msg here where msg_id=$id";

$qid=mysql_query($query);



just a small learifiactions..

if u post here what excatly want to do and ur code..i will post the code here..

Hope this help

Lk :o)
0
 
lokeshvCommented:
i can got that u want to display all the messages on first page...but what on next page ?


for first page use this ..


<?
$conn=mysql_pconnect("urserver","username","password");
if(!$conn){
        echo"cant connect";
        die;
}

mysql_select_db("database_name");

$qid=mysql_query("select * from txts");

while($row=mysql_fetch_array($qid);$i++){
?>
<html>
<table>
<tr><td><?=$row[heading]?></td></tr>
<tr><td><?=$row[message]?></td></tr>
<tr><td><a href="your_file.php?message_id=<?=$row[id]?>">Your Link</a></td></tr>
</table>

<br><br>
<?}?>
</html>
0
 
lokeshvCommented:
hope this helps..


Lk:)
0
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Nick500000Author Commented:
Thanks for your help on the first page... i'll get to work on that straight away.

For the second page, I have already found a script for that, but I need to add some more code which will simply place the text from the mysql field 'message' into a variable (possibly called 'message'!). But the message must be selected according to the 'id', Which will have been passed by the link scripted into your example above...

So really I want.

$message = AND THEN THE MYSQL SYNTAX HERE.....

Thanks,
Nick!
0
 
lokeshvCommented:
ok here is ur PHP code for second page

<?
$id=$message_id; //this is got from first page

$query="select message from txts where id=$id";

$qid=mysql_query($query);

if(!$qid){
       echo 'Error:'.mysql_error();
}

$row=mysql_fetch_array($qid);

//your varaible

$message=$row[message];

?>


hope this will solve ur problem..

Lk :o)
0
 
Nick500000Author Commented:
O.K, thanks alot... I try that now.
0
 
Nick500000Author Commented:
I am sure that there is nothing wrong with your code, but all I get is a blank out put from the query.... even though I have set up some test values.... I have checked this using phpmyadmin. Maybe there is some thing wrong with my set up. Do I need some Unique key/index? Here is the structure of my table:

#
# Table structure for table txts
#

CREATE TABLE txts (
   id varchar(5) NOT NULL auto_increment,
   heading mediumtext NOT NULL,
   message longtext NOT NULL,
   cat text NOT NULL,
   UNIQUE id (id)
);

Is there something wrong with this?

any ideas would be helpful.

Thanks,
Nick!
0
 
Nick500000Author Commented:
Well,

it's not strictly blank, all I get is:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=Content-Type content="text/html; charset=windows-1252"></HEAD>
<BODY></BODY></HTML>

So the conditions of the while loop are being met straigth away, resulting in it not running?

0
 
Nick500000Author Commented:
And the second script just says, cant connect. Maybe something up with my host!
0
 
lokeshvCommented:
first page ..

replace while($row=mysql_fetch_array($qid);$i++)


from

while($row=mysql_fetch_array($qid))

and check you have any data in the tbale or not ?


second page...

add on top


$conn=mysql_pconnect("urserver","username","password");
if(!$conn){
       echo"cant connect";
       die;
}



if this still doesnt solve ur prblm ...post ur code here ..

Lk
0
 
Nick500000Author Commented:
I am getting 'can't connect' on all the scripts now. I am sure that this something wrong with my host. I'll try on another host.... If that doesn't work i'll post the code!
0
 
Nick500000Author Commented:
Hey,

I don't know whether this is relevant, but a script I found on php.net, has this as the connect string:

$conn = mysql_connect("localhost", "username", "password");

but your script has:

$conn = mysql_pconnect("localhost","username","password");

Notice the extra 'p'.... is this what may be causing the 'can't connect'?

Nick!

0
 
Nick500000Author Commented:
Yes, that's what was causing it.

I removed the 'p', and the script works perfectly.... I emailed support, and they told me that using pconnect was specifically banned on their servers. So not your fault at all!

Thanks so much.

Here's your points....

-----
Nick!
-----
0
 
Nick500000Author Commented:
Thanks again!

Nick!!!
0
 
lokeshvCommented:
Anytime...

thanks for points:o)

Lk
0

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