Solved

Counting Query

Posted on 2002-04-12
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Last Modified: 2013-12-24
I'm working on a web based IT knowledbase type app for my personal use. I'm trying to accomplish something I have seen on other websites. I have a DB with two tables. One table has all the different categories and their category id, and the other table has a the actual content, category ID, etc. (Look at the attached code below and look at the CFQUERY pulling out of the KNOWLEDGEBASE table or download a copy of this DB here: http://www.georgelemos.com/glkb.zip)

If you go to http://www.georgelemos.com/categories.cfm you will see the template I am working on. You'll notice the (4) next to each category. What I want to do, is query the KNOWLEDGEBASE table and count how many articles I have stored in the DB for each CATEGORY. Then next to each category have a number displaying how many articles for that CATEGORY are stored in the DB.

I have tried a few different ways but I really came up with nothing that works. Right now all its doing is displaying how many entries are in cetegory 1 (which are 4) I am assuming there's some type of CFLOOP needed which I am really awful with.

If someone has a piece of code available that could help me out I would greatly appreciate it. The code below is what I have running on the page URL listed above.

Thanks!

<CFQUERY NAME="CATZ" DATASOURCE="GLKB">
   Select CATID, CATEGORY
   From CATEGORIES
   Order By CATEGORY
</CFQUERY>



<CFQUERY NAME="NUMZ" DATASOURCE="GLKB">
  SELECT CATEGORIES.CATEGORY, CATEGORIES.CATID, (SELECT Count(*)
  FROM KNOWLEDGEBASE where KNOWLEDGEBASE.CATEGORY = CATEGORIES.CATID) AS CategoryCount
  FROM CATEGORIES;
</CFQUERY>









<HTML>
<HEAD>
 <TITLE>Categories</TITLE>
 <META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=iso-8859-1">
 <LINK REL="stylesheet" HREF="glcss.css" TYPE="TEXT/CSS">
</HEAD>






<TABLE WIDTH="525" CELLSPACING="3" CELLPADDING="3">
<TR>                                          
<CFOUTPUT QUERY="CATZ">
<TD><A HREF="catpage.cfm?CATID=#CATZ.CATID#">#CATZ.CATEGORY#</A> (#NUMZ.CategoryCount#)<BR>
</TD>
<CFIF CATZ.CURRENTROW MOD 2 IS 0>
</TR>
<TR>
</CFIF>
</CFOUTPUT>
</TABLE>


</BODY>
</HTML>
0
Comment
Question by:gplemos
  • 3
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7 Comments
 
LVL 19

Expert Comment

by:cheekycj
ID: 6936900
<CFQUERY NAME="CATZ" DATASOURCE="GLKB">
  Select CATID, CATEGORY
  From CATEGORIES
  Order By CATEGORY
</CFQUERY>

<cfloop query="CATZ">
<CFQUERY NAME="NUMZ" DATASOURCE="GLKB">
 SELECT CATEGORIES.CATEGORY, CATEGORIES.CATID, COUNT(*) AS CategoryCount
FROM KNOWLEDGEBASE, CATEGORIES where KNOWLEDGEBASE.CATEGORY = CATZ.CATID
AND CATEGORIES.CATID = KNOWLEDGEBASE.CATEGORY
</CFQUERY>
</cfloop>

should work.

Just use the query numz now to display the stuff like:

<cfoutput query="NUMZ">
#NUMZ.CATEGORY# (#NUMZ.CategoryCount#)<br>

CJ
0
 
LVL 19

Expert Comment

by:cheekycj
ID: 6936904
oops forgot the ending </cfoutput>:
<cfoutput query="NUMZ">
#NUMZ.CATEGORY# (#NUMZ.CategoryCount#)<br>
</cfoutput>

0
 
LVL 1

Accepted Solution

by:
ndintenfass earned 100 total points
ID: 6937437
Looping over a query, though, can be "expensive" overhead.  You can accomplish this in one query like this:

<CFQUERY NAME="CATZ" DATASOURCE="GLKB">
  Select     CATEGORIES.CATID,
                 CATEGORIES.CATEGORY,
               COUNT(KNOWLEDGEBASE.CATEGORY) As CategoryCount
               
  From           KnowledgeBase RIGHT JOIN CATEGORIES ON KNOWLEDGEBASE.CATEGORY = CATEGORIES.CATID
 
  GROUP BY      CATEGORIES.CATID,CATEGORIES.CATEGORY
 
  Order By      CATEGORIES.CATEGORY
</CFQUERY>

<HTML>
<HEAD>
<TITLE>Categories</TITLE>
<META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=iso-8859-1">
<LINK REL="stylesheet" HREF="glcss.css" TYPE="TEXT/CSS">
</HEAD>

<TABLE WIDTH="525" CELLSPACING="3" CELLPADDING="3">
<TR>                                          
<CFOUTPUT QUERY="CATZ">
<TD><A HREF="catpage.cfm?CATID=#CATZ.CATID#">#CATEGORY#</A> (#CategoryCount#)<BR>
</TD>
<CFIF CATZ.CURRENTROW MOD 2 IS 0>
</TR>
<TR>
</CFIF>
</CFOUTPUT>
</TABLE>


</BODY>
</HTML>


OR, if you want only the categories that do have entries in the knowledge base, you can simply have the query be:


  Select     CATEGORIES.CATID,
                 CATEGORIES.CATEGORY,
               COUNT(KNOWLEDGEBASE.CATEGORY) As CategoryCount
  From           CATEGORIES,
                 KNOWLEDGEBASE
  WHERE          KNOWLEDGEBASE.CATEGORY = CATEGORIES.CATID
  GROUP BY      CATEGORIES.CATID,CATEGORIES.CATEGORY
  Order By      CATEGORIES.CATEGORY
0
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LVL 19

Expert Comment

by:cheekycj
ID: 6937474
>Looping over a query, though, can be "expensive" overhead

true but it really does depend on the data set.

If the categories is under like 500 .. its probably
fine performance wise.

CJ
0
 

Author Comment

by:gplemos
ID: 6937520



Using the code below on URL:
http://www.georgelemos.com/categories2.cfm

I get the error:

"ODBC Error Code = 37000 (Syntax error or access violation)
[Microsoft][ODBC Microsoft Access Driver] You tried to execute a query that does not include the specified expression 'CATEGORY' as part of an aggregate function.



The error occurred while processing an element with a general identifier of (CFQUERY), occupying document position (8:1) to (8:39)."


Any suggestions?













<CFQUERY NAME="CATZ" DATASOURCE="GLKB">
 Select CATID, CATEGORY
 From CATEGORIES
 Order By CATEGORY
</CFQUERY>

<cfloop query="CATZ">
<CFQUERY NAME="NUMZ" DATASOURCE="GLKB">
SELECT CATEGORIES.CATEGORY, CATEGORIES.CATID, COUNT(*) AS CategoryCount
FROM KNOWLEDGEBASE, CATEGORIES where KNOWLEDGEBASE.CATEGORY = CATZ.CATID
AND CATEGORIES.CATID = KNOWLEDGEBASE.CATEGORY
</CFQUERY>
</cfloop>







<HTML>
<HEAD>
<TITLE>Categories</TITLE>
<META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=iso-8859-1">
<LINK REL="stylesheet" HREF="glcss.css" TYPE="TEXT/CSS">
</HEAD>






<cfoutput query="NUMZ">
#NUMZ.CATEGORY# (#NUMZ.CategoryCount#)<br>
</cfoutput>



</BODY>
</HTML>
0
 
LVL 1

Expert Comment

by:ndintenfass
ID: 6937757
I think you need a GROUP BY clause in the query (see my comment from above about doing it all in one query -- same idea)
0
 

Author Comment

by:gplemos
ID: 6940381
That did the trick. Thank you to both of you.
0

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