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std::wstring wont work with overloaded std::operator<<

Posted on 2002-04-15
2
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Last Modified: 2013-12-14
hello experts,

can anyone tell me why this code compiles and runs:
---------------------------------------------------
#include <string>
#include <iostream>

using namespace std ;

void main()
{
    string msg="Hello!";
    cout << msg << endl;
}
-------------------------------------------------

whereas this code (using std::wstring instead of std::string)
-------------------------------------------------
#include <string>
#include <iostream>

using namespace std ;

void main()
{
    wstring msg=L"Hello";
    cout << msg << endl;
}
-------------------------------------------------
produces the following error:

error C2679 binary '<<' : no operator found which takes a right-hand operand of type 'std::wstring' (or there is no acceptable conversion)
?

string, wstring (calsses) and operator<< (function) are all templates defined in <string>.
what do i have to do in order to be able to use operator<< on types templated on std::basic_string other than std::string?

thanks!
0
Comment
Question by:managair
2 Comments
 
LVL 86

Accepted Solution

by:
jkr earned 50 total points
ID: 6942035
Because "cout" has no "operator << (const wstring&);" - use "wcout" instead, e.g.

include <string>
#include <iostream>

using namespace std ;

void main()
{
   wstring msg=L"Hello";
   wcout << msg << endl;
}

See also "iostream", it has mutliple objects for handling UNICODE:

IOSTREAM:extern _CRTIMP ostream cout; // ANSI
IOSTREAM:extern _CRTIMP wostream wcout, wcerr, wclog; // UNICODE


0
 

Author Comment

by:managair
ID: 6942073
it makes sense that if i use a wstring i should use a wostream.

thanks!
0

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