Solved

problem opening executable file while inside executable

Posted on 2002-04-17
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233 Views
Last Modified: 2010-04-02
Inside a given a program c:\program.exe, I have the following code:

filebuf *fb=new filebuf;
int mode=ios::binary | ios::in | ios::nocreate;
fb->open("c:\program.exe",mode);
if (!fb->is_open())
  and this test always fails

Is the operating system blocking me on this?  Is there some way to copy the executable to another file and open that?

Thanks
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Comment
Question by:Ashurbanipal
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5 Comments
 
LVL 86

Expert Comment

by:jkr
ID: 6947907
Try

fb->open("c:\\program.exe",mode); // note the double backslash!
0
 

Author Comment

by:Ashurbanipal
ID: 6947967
actually the code looks more like:

std::string file=GetCommandLine();
fb->open(file.c_str(),mode);

When I look at the contents of "file" there doesn't seem to be any problem.  I'm opening other files with no problem and am just having a problem with the executable.
0
 
LVL 16

Accepted Solution

by:
AlexNek earned 100 total points
ID: 6948036
I already realized master-slave architecture with one Exe. I have no problem with this line:
FILE*     fp = fopen(ModuleName, "rb");
0
 
LVL 16

Expert Comment

by:AlexNek
ID: 6948264
I already realized master-slave architecture with one Exe. I have no problem with this line:
FILE*     fp = fopen(ModuleName, "rb");
0
 
LVL 16

Expert Comment

by:AlexNek
ID: 6948519
I already realized master-slave architecture with one Exe. I have no problem with this line:
FILE*     fp = fopen(ModuleName, "rb");
0

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