Solved

Using of JavaBean

Posted on 2002-04-18
9
341 Views
Last Modified: 2013-11-24
Hi All Experts,

I have difficulties making my JavaBean works. It's just a simply program which uses 1 JSP and 1 Bean program. I've attached the programs and the errors encountered for your reference.

************
Bean
************

import java.io.Serializable;

public class footer1 implements Serializable{

  private String message = "No message.";

  public String getMessage() {
    return message;
  }
   
  public void setMessage(String s) {
    message = s;
  }
}

***********
JSP
***********

<HTML>
<BODY BGCOLOR="WHITE">
  <jsp:useBean id="MyMessage" class="footer1"></jsp:useBean>
  <OL>
   <LI> Initial Message (using getProperty):
     <I> <jsp:getProperty name="MyMessage" property="message" /> </I>
   <LI> <jsp:setProperty name="MyMessage" property="message" value="Meeting" />
     Secret message (after setting):
     <I> <jsp:getProperty name="MyMessage" property="message" /> </I>
  </OL>
 </BODY>
</HTML>

********************
Errors
********************

org.apache.jasper.JasperException: Unable to compile class for JSP

An error occurred at line: 8 in the jsp file: /myjsp/footer.jsp

Generated servlet error:
C:\jakarta-tomcat-4.0\work\Standalone\localhost\_\myjsp\footer$jsp.java:60: Class org.apache.jsp.footer1 not found.
        footer1 MyMessage = null;
        ^
An error occurred at line: 8 in the jsp file: /myjsp/footer.jsp

Generated servlet error:
C:\jakarta-tomcat-4.0\work\Standalone\localhost\_\myjsp\footer$jsp.java:63: Class org.apache.jsp.footer1 not found.
          MyMessage= (footer1)

Is there any errors with my codes? Could anyone help me with this.... By the way, I'm using Tomcat. I've tried in Jrun, my codes are ok and will not generate any errors. So is there something that Tomcat is not letting my codes to be compiled and run successfully? Please advise.

Thank you.
0
Comment
Question by:tigerSG
  • 4
  • 3
  • 2
9 Comments
 
LVL 9

Expert Comment

by:Venci75
ID: 6949858
compile your footer1 class and put it to the tomcat's 'classes' directory
0
 

Author Comment

by:tigerSG
ID: 6949869
By the when I installed Tomcat, there isn't any classes directory. Hence, I created a classes directory under WEB-INF :
Tomcat\webapps\ROOT\WEB-INF\classes

Am I right?
0
 

Expert Comment

by:jodear
ID: 6949903
Yup, that should work if your jsp is in the folder Tomcat\webapps\ROOT
0
 

Expert Comment

by:jodear
ID: 6949905
Yup, that should work if your jsp is in the folder Tomcat\webapps\ROOT
0
3 Use Cases for Connected Systems

Our Dev teams are like yours. They’re continually cranking out code for new features/bugs fixes, testing, deploying, testing some more, responding to production monitoring events and more. It’s complex. So, we thought you’d like to see what’s working for us.

 

Accepted Solution

by:
jodear earned 30 total points
ID: 6949955
Also, your bean should be named footer1.java.  If you place footer1.java in the \webapps\ROOT\WEB-INF\classes folder, as Venci75 suggested, compile it there also so that footer1.class will also be created in the same folder.

If you have any trouble compiling footer1.java, just respond here.
0
 

Author Comment

by:tigerSG
ID: 6950421
Well, I have compiled my footer1.java and it's successful. It's just having problem when I'm trying to use it as a bean. I've tried using jrun to run my program, it works. Hence, I'm confused why it's not working in Tomcat.
0
 
LVL 9

Expert Comment

by:Venci75
ID: 6950432
Does the directory
Tomcat\classes
exist on your machine?
0
 

Author Comment

by:tigerSG
ID: 6952268
Nope. There's no such directory in my machine. I've downloaded the software from http://jakarta.apache.org/tomcat and after unzipping it, a directory named jakarta-tomcat-4.0 resides in my machine. By the way, do I need to setup anything in the xml files?
0
 

Expert Comment

by:jodear
ID: 6961969
You don't need to setup anything in the XML files.  A Java bean is usually packaged.  What you have is a java class file, so you can't useBean it.  You can import it though, if you placed it at \WEB-INF\classes folder, or as Venci75 says, at the \jakarta-tomcat-4.0\classes folder.  Then you have to restart Tomcat.

If you really want to use it as a Java bean, you have to redo your footer class as follows:

package myPack;

import java.io.Serializable;

public class footer1 implements Serializable{

 private String message = "No message.";

 public String getMessage() {
   return message;
 }
   
 public void setMessage(String s) {
   message = s;
 }
}

Compile it then place it in the folder \WEB-INF\classes\myPack\.  If there's none, make one.  Make sure that you follow the upper and lower cases since Java is case sensitive.

Hope that works!
0

Featured Post

Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
DO we need Java installed on a Windows PC and WHY ? 13 95
maven example error 3 52
servlet  URL Rewriting 1 25
web services creation SOAP vs REST 5 17
This was posted to the Netbeans forum a Feb, 2010 and I also sent it to Verisign. Who didn't help much in my struggles to get my application signed. ------------------------- Start The idea here is to target your cell phones with the correct…
I had a project requirement for a displaying a user workbench .This workbench would consist multiple data grids .In each grid the user will be able to see a large number of data. These data grids should allow the user to 1. Sort 2. Export the …
Viewers learn about the third conditional statement “else if” and use it in an example program. Then additional information about conditional statements is provided, covering the topic thoroughly. Viewers learn about the third conditional statement …
Viewers will learn one way to get user input in Java. Introduce the Scanner object: Declare the variable that stores the user input: An example prompting the user for input: Methods you need to invoke in order to properly get  user input:

914 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

13 Experts available now in Live!

Get 1:1 Help Now