access another class without construct the class.

Sorry I don't understand what your problem is?

Not  problem.  You are calling t1.get() but there seems to be no instantiation of that variable.  You should create a new constructor for your T1 class that doesn't include an endless loop, set the boolean value to true sometime.  Then use that variable....Something like the following...
//****** T1.class
public class T1 {
   private int contents=2;
   private boolean available = false;
   public T1() {
         while (available==false)
         {
         }
    }
    public T1(boolean ref){
          available = ref;
     }
    public int get() {
       available = false;
       return contents;
   }

   public void put(int value) {
       contents = value;
       available = true;
   }

   public static void main(String[] args) {
       T1 t1 = new T1();
   }
}
//*** T1 End

//********** T2.class
public class T2 {
    private T1 t1 = new T1(true);
    public T2() {
    //     t1.put(10);
         System.out.println("value of contents in t1: " + t1.get());
         t1.put(55);
          System.out.println("value of contents in t1: " + t1.get());
    }
   public static void main(String[] args) {
       T2 t2 = new T2();
   }
}
//********** T2 End

Thanks. Actually what i want to do is, T1 is a daeman process, it will be run all the time. T1 act as a Schedule and contain a vector to keep all the running time for all tasks. T2 is used to update the vector in T1. T2 is only run whenever running time is need to update. so T1 should get the lastest running time for a task. If i instantiate T1 in T2, it will start another Schedule, it may not be correct, am i right?

Just maintain a static variable referencing the last T1 that was constructed.

Sorry, let me make my question more clear. I have two class, Schedule and SchUpdate. Schedule is run as a daemon process, it contains a vector saving running time. SchUpdate is run whenever running time updating is needed. So the point is, how SchUpdate detect the existing Schedule program that is running and change the value of vector.
thanks for help.

Just have Schedule maintain a static reference to itself:

class Schedule
{
  public static Scedule Instance;

  public Schedule()
  {
     Instance = this;
     ...
  }
...
}

Then you can simply access Schedule using:

Schedule.Instance.whatever();

in Schedule.Instance.whatever();
did u mean whatever() is method in Schedule? ( get & put)

i change to this:
public class t1 {
  private int contents=2;
  private boolean available = false;
  public static t1 Instance;

  public t1() {
       Instance = this;
        while (available==false)
        {
        }
   }
   public t1(boolean ref){
         available = ref;
    }
   public int get() {
      available = false;
      return contents;
  }

  public void put(int value) {
      contents = value;
      available = true;
  }

  public static void main(String[] args) {
      t1 tt1 = new t1();
  }
}

public class t2 {
   public t2() {
        System.out.println("value of contents in t1: " + t1.Instance.get());
   }
  public static void main(String[] args) {
      new t2();
  }
}

error, NullPointerException in t1.Instance.get();

> did u mean whatever() is method in Schedule? ( get & put)

yes.

> error, NullPointerException in t1.Instance.get();

Yes, because your scheduler has not been started.
It makes no sense to call the object before it is created.

i run t1 before t2. the error still the same

Are they running in different JVM's?
If so you'll have to use RMI or something similiar, or alternatively run them in the same JVM.

i not understand wht is running in different JVM. i just run both class independently.

> java t1
> java t2

Then they are running in different JVM's.
Why don't you run both classes in the same JVM?

i prefer run in same JVM too. but Schedule might be a daemon process, while SchUpdate is only run when update is needed. simple say is, Schedule is back-end process, while SchUpdate is front-end process. =)

so what is ur suggestion?

Make your constructor protected and maintain a reference to itself.
To get a instacne of the class always use a instanceOf method
Your class would be something like this
//****** T1.class
public class T1 {
   private int contents=2;
   private boolean available = false;
   protected static T1 instance;
   protected  T1() {
         while (available==false)
         {
         }

    instance = this;
    }
    public int get() {
       available = false;
       return contents;
   }

   public void put(int value) {
       contents = value;
       available = true;
   }

   public static void main(String[] args) {
       T1 t1 = new T1();
   }

   public static T1 instanceof()
   {
      if( instance == null)
         instance = new T1();
      return instance;

}
//*** T1 End

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hi mickoo, how T2.java should be write as?

public class T2 {
   
    public T2() {
    T1 t1 = T1.instanceOf();
         System.out.println("value of contents in t1: " + t1.get());
    }
   public static void main(String[] args) {
       T2 t2 = new T2();
   }
}
//********** T2 End

i compile the code, but dun have output.
i change following code :

public static T1 instanceof()
  {
     if( instance == null)
        instance = new T1();
     return instance;

TO :

public static T1 instanceOf()
{
     if( instance == null)
        instance = new T1();
     return instance;
}

is correct, right?

> so what is ur suggestion?

There are many options open to you. RMI is one option.

That code will create a NEW instance of T1, and will not call the existing running daemon.

That code will create a NEW instance of T1, and will not call the existing running daemon.
> which code? ^_^

hi object, do u have any example to use RMI for my program? thanks alot

chencc77 is awaiting response on follow up question.
Moondancer - EE Moderator

:-)