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Getting rid of ' in strings

Hi everyone,

I have a variabel called strName and sometimes there will be an apostrofe (') in this string.
But don't want to save this '. Is there a way to get rid of these '.
So what I am looking for is a function.

Thanks
Hinke
0
hinkeltje
Asked:
hinkeltje
1 Solution
 
GunsenCommented:
Replace() function in VB6

or

Sub ReplaceStr(St As String, ByVal SubSt As String, ByVal NewSt As String)
'  Replaces every occurence of SubSt in St with NewSt

  Dim I As Integer

  Do
    I = InStr(1, St, SubSt, 1)
    If I > 0 Then
      St = Left$(St, I - 1) + NewSt + Mid$(St, I + Len(SubSt))
    End If
  Loop Until I = 0
End Sub
0
 
ajexpertCommented:
you can use Replace function
For Example
strString = "'Hinke'"
strString = Replace(strString, "'", "")
MsgBox strString
0
 
ajexpertCommented:
Cut and Paste above code in VB and see the results
0
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deightonCommented:
why don't you want to save it?  If they are causing sql statements to fail, then you should double up the apostrophe in the sql string.

e.g

select * from tablew where name = 'O''Brien'
0
 
mdouganCommented:
Another option, if you are saving these into a database and that is why you are trying to get rid of them, is to use the ado command object with ado parameter objects.  If you put the string into the value property of a parameter object and append it to a command object, then when you run the insert/update query through the command object, it will handle the single quote perfectly.  Actually, it handles all "problem" characters perfectly, you don't have to worry about wrapping strings in quotes or not wrapping numbers in quotes.  You don't have to worry about date formats or putting # signs around dates or anything like that.  It's all I use anymore.....

By the way, if you are getting rid of the ' in names like O'Brian, you're probably going to piss off a lot of people, if you ever decide to mailmerge out a letter with their name on it like OBrian.
0
 
rkot2000Commented:
I am converting ' and " to ` and ` works fine with sql statements.

Public Function FilterString(ByVal lvsIn As String, _
                             ByVal lvlConversion As geConversion) As String
  lvsIn = Replace(lvsIn, Chr(44), " ")
  lvsIn = Replace(lvsIn, Chr(39), Chr(96))
  lvsIn = Trim$(Replace(lvsIn, Chr(34), Chr(96)))
 
  Select Case lvlConversion
    Case geConversion.awpProper
      FilterString = StrConv(lvsIn, vbProperCase)
    Case geConversion.awpLower
      FilterString = StrConv(lvsIn, vbLowerCase)
    Case geConversion.awpUpper
      FilterString = StrConv(lvsIn, vbUpperCase)
    Case geConversion.awpNone
      FilterString = lvsIn
  End Select
End Function
0
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