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Regular expression woes

Posted on 2002-04-20
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Last Modified: 2008-03-06
I want to find every occurance of a string and be able to replace it with a different string depending on a parameter passed.  (Cryptic, I know)

<mytag=some parameter>stuff inside!</mytag> text inbetween <mytag=param again>more stuff even</mytag>

The problem I am having is that my code will give me "stuff inside!</mytag> text inbetween <mytag=param again>more stuff even" instead of each one seperately.

Here is my code:

$regexp="\[mytag\=([a-zA-Z0-9 ]+)\]([[:graph:] ]+)\[\/mytag\]";
while(eregi($regexp,$message,$regs)){
  if(str_replace(" ","",strtolower("Tom Apps com"))==str_replace(" ","",strtolower($regs[1]))){
    $message=eregi_replace($regexp,"\\2",$message);
  }else{
    $message=eregi_replace($regexp,"",$message);
  }
}
echo $message;

Help if you can! :)
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Question by:VBTom
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LVL 6

Accepted Solution

by:
andreif earned 100 total points
ID: 6959072
Problem is that program looks for the longest match.
To make it look for the shortest, add ? to * or +

Your RegExp:

$regexp="\[mytag\=([a-zA-Z0-9 ]+)\]([[:graph:] ]+)\[\/mytag\]";

should read as

$regexp="\[mytag\=([a-zA-Z0-9 ]+)\]([[:graph:] ]+?)\[\/mytag\]";
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