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Strange runtime error in simple program

Posted on 2002-04-21
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Last Modified: 2010-04-02
this is just a fairly simple program i wrote for school
but i am getting a strange error during runtime
from a list of 7 options, when i choose 3 of them the program crashes in windows and gives a core dump in unix
these 3 are choice #2 #4 #6. the code for each of them is quite similar no obivious reason for these errors
is there some kind of pattern? everyother choice seems to suffer from this. i am using a switch statement in the main function to call the appropriate class member functions.

the code is rather long to post here so you can access the zip file containing all the files here:
http://gdstudios.hypermart.net/code.zip

p.s. some of the functions are left as stubs, that was intentional
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Question by:grfik
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3 Comments
 
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Accepted Solution

by:
LoungeLizard earned 100 total points
ID: 6958608
You use pointers without first initialising them! Your main should look something like:

int main()
{
   int choice;
   Triangle *t = new Triangle;
   RightTriangle *rt = new RightTriangle;
   Quads *q = new Quads;
   Parallelogram *p = new Parallelogram;
   Rhombus *r = new Rhombus;
   Rectangle *rect = new Rectangle;
   Square *s = new Square;
   
   do
   {
      displayMenu();
      cin >> choice;

      switch(choice)
      {
         case 1:
            t->getInfo();
            t->output();
            break;
         case 2:
            rt->getInfo();
            rt->output();
            break;
         case 3:
            q->getInfo();
            q->output();
            break;
         case 4:
            p->getInfo();
            p->output();
            break;
         case 5:
           
            r->getInfo();
            r->output();
            break;
         case 6:
           
            rect->getInfo();
            rect->output();
            break;
         case 7:
           
            s->getInfo();
            s->output();
            break;
         case 0:
            cout << "Good Bye\n";
            break;
         default:
            cout << "Error!\n";
            return 1;
      }// switch

   } while(choice != 0);

   return 0;
}
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LVL 2

Expert Comment

by:LoungeLizard
ID: 6958612
You could still put the new's inside the switch statement, if you want to create new variables every time the switch is executed.
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Author Comment

by:grfik
ID: 6959060
umm i knew there would be a simple solution, thx loungelizard
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