?
Solved

AppIsolated

Posted on 2002-04-23
4
Medium Priority
?
605 Views
Last Modified: 2009-07-29
I have a code which helps me to create web site & do the necessary settings on the property. But when come to this AppIsolated, I encountered some problems here.

from my code, I can easily set my AppIsolated to Low or Medium Pool & the site can be created successfully. Anyhow, when I try to create it to be High Isolated, I can't browse the web page under this site.

I read through MSDN & found out that if you were to create a site with High Isolated, you'd have to have a Com+ package running for it as well.

Please read
Web Security: Part 2: Introducing the Web Application Manager, Client Authentication Options, and Process Isolation
in MSDN.

in that case, can someone illustrate me how to get this thing done? Is it to write to registry? or create a Com+ Application programmatically?

Please provide the source code here as well. thanks.

my current code looks like this.

Set objApplication = GetObject("IIS://" & v_strServerNm & "/W3SVC/" & intSiteIndex & "/ROOT")
    With objApplication
        .AppRoot = "IIS://" & v_strServerNm, "/LM"
        .AppFriendlyName = "Default Application"
        .AppIsolated = 1
        .AccessRead = True
        .AccessExecute = True
        .SetInfo
    End With

thanks!
0
Comment
Question by:mah5696
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
4 Comments
 
LVL 3

Expert Comment

by:n_narayanan
ID: 6962244
One reason could be,

If you have used any "session" then it will not load.

Try removing the Session or set the Isolated level as low

Narayanan
0
 

Author Comment

by:mah5696
ID: 6962306
n_narayanan, I wish u get me right..
I want to set up a web site with my Application be Isolated. meaning my AppIsolated = 1 '(High)

pls provide the appropriate solution. thanks.
0
 
LVL 5

Accepted Solution

by:
ianouii earned 800 total points
ID: 7163937
ok, try this.

Set objApplication = GetObject("IIS://" & v_strServerNm & "/W3SVC/" & intSiteIndex & "/ROOT")
   With objApplication
       .AppRoot = "IIS://" & v_strServerNm, "/LM"
       .AppFriendlyName = "Default Application"
       '.AppIsolated = 1
       .AppCreate2 1
       .AccessRead = True
       .AccessExecute = True
       .CreateA
       .SetInfo
   End With

good luck.
0
 

Author Comment

by:mah5696
ID: 7164024
thanks. it works...
0

Featured Post

What does it mean to be "Always On"?

Is your cloud always on? With an Always On cloud you won't have to worry about downtime for maintenance or software application code updates, ensuring that your bottom line isn't affected.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

There are many ways to remove duplicate entries in an SQL or Access database. Most make you temporarily insert an ID field, make a temp table and copy data back and forth, and/or are slow. Here is an easy way in VB6 using ADO to remove duplicate row…
When trying to find the cause of a problem in VBA or VB6 it's often valuable to know what procedures were executed prior to the error. You can use the Call Stack for that but it is often inadequate because it may show procedures you aren't intereste…
Get people started with the process of using Access VBA to control Outlook using automation, Microsoft Access can control other applications. An example is the ability to programmatically talk to Microsoft Outlook. Using automation, an Access applic…
Show developers how to use a criteria form to limit the data that appears on an Access report. It is a common requirement that users can specify the criteria for a report at runtime. The easiest way to accomplish this is using a criteria form that a…
Suggested Courses
Course of the Month14 days, 15 hours left to enroll

770 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question