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Line count by group

Posted on 2002-04-23
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Last Modified: 2008-02-01
For the life of me I can not remember how to do the following:

Given a table with the following:
ordr_sys_key_id, ordr_dt, locn_sys_key_id
1001, 2002/03/04, 305
1003, 2002/03/04, 305
1011, 2002/03/04, 305
1002, 2002/03/04, 306
1004, 2002/03/04, 306
1012, 2002/03/04, 306

I want ro produce something like this in a query:
1001 2002/03/04 305 1
1003 2002/03/04 305 2
1011 2002/03/04 305 3
1002 2002/03/04 306 1
1004 2002/03/04 306 2
1012 2002/03/04 306 3

Thanks,
Darek


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Question by:dtomyn
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by:ScottPletcher
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Something like this should do it:

SELECT ordr_sys_key_id, ordr_dt, locn_sys_key_id,
    (SELECT COUNT(*) + 1
     FROM tablex x2
     WHERE x1.locn_sys_key_id = x2.locn_sys_key_id
     AND x1.ordr_sys_key_id < x2.ordr_sys_key_id) AS 'Line#'
FROM tablex x1
ORDER BY locn_sys_key_id, ordr_sys_key_id

Notes:
*) this method may not perform very well on a really large table
*) haven't tested this yet -- will do so ASAP

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ScottPletcher earned 100 total points
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Oops, got some logic backwards.  In the WHERE, need to change "<" to ">".  Also, I didn't format the date properly.  Here is the corrected query:

SELECT ordr_sys_key_id, CONVERT(CHAR(10),ordr_dt,111) AS 'Order Date', locn_sys_key_id,
   (SELECT COUNT(*) + 1
    FROM tablex x2
    WHERE x1.locn_sys_key_id = x2.locn_sys_key_id
    AND x1.ordr_sys_key_id > x2.ordr_sys_key_id) AS 'Line#'
FROM tablex x1
ORDER BY locn_sys_key_id, ordr_sys_key_id
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Author Comment

by:dtomyn
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Perfect (basically), thanks.
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Expert Comment

by:gchavezr
Comment Utility
I´m just looking
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