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Variable Length Strings -- Format of Extra 10 Bytes

When using variable length strings (which is a GOOD thing), what is the format for the extra 10 bytes that are used?
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GivenRandy
Asked:
GivenRandy
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AzraSoundCommented:
Is this what you are after?

http://www.vb2themax.com/HtmlDoc.asp?Table=Articles&ID=30

Gives description of internal storage of strings in memory
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rspahitzCommented:
Azra, that's interesting.  It appears that the second page has the relevant information.

Here's some string information:

Fixed-length strings are good if you know the exact size of the data to be saved, and will usually run much faster than a variable length string of th same size.

Variable length strings have a certain amount of overhead in order to know how much data is in the string.

A string constant may have a direct memory reference (in-line reference) or it may have an indirect memory reference (address pointer to where the string is found.)

--
Variable length string will usually have the indirect memory pointer, meaning that their structure usually consists of a few bytes indicating the length of the file, then an address indicating where the text is located.  To view the actual data, you need to follow the address and look for the specified number of bytes (maybe minus one.)

>what is the format for the extra 10 bytes
I haven't looked lately at the details, but hopefully the above is enough info for you.
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GivenRandyAuthor Commented:
Not really sure if it answers it (I might have missed the answer in there). I figured there were about 4 bytes for length, 4 bytes for memory address, 2 for something else. Was looking for the layout of that. Was that in there?

I try to use variable-length strings unless absolutely required (but other options are usually better). VB.NET drops fixed-length strings.
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AzraSoundCommented:
The figure on Page 2 seems to summarize it in its caption:

"The LenB function returns the value of the double word that immediately precedes the first character. The Dim x As String statement reserves 4 bytes for the descriptor, but no memory is allocated for the string until the first assignment occurs."

So, to me, that says:

8 bytes =
4 bytes for the double word telling length of string +
4 bytes for the descriptor
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AzraSoundCommented:
I'm not sure where those other 2 bytes you are referring to are coming from.  Are you sure it is 10 bytes?
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GivenRandyAuthor Commented:
For storage size, online help says "10 bytes + string length" for variable-length strings.
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rspahitzCommented:
I thought that a user-defined type might give me a clue:

Private Type x
  s As String
End Type

Private Sub Command2_Click()
  Dim y As x
  y.s = String$(65534, "q")
  Open "C:\qaz.txt" For Binary As #1
  Put #1, , y
  Close 1
End Sub

The output file contains a leading hex sequence of 2 bytes for strings less than 65535, and 6 bytes for strings of 65535 or more (64K - 1)

I suspect that the extra two bytes is used to differentiate between a "near pointer" and a "far pointer."
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